Back to marketplace

TM: Variable Oxidation States & Redox

No description yet. This curated deck is ready for daily study.

Total cards: 17•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (17)

#1
Front (Question)

Do transition elements show variable oxidation states

Back (Answer)

Yes

#2
Front (Question)

How is variable oxidiation states utilised in tollen’s reagent to test for an aldehyde

Back (Answer)

Ag+ in [Ag(NH3)2]+ reduced to Ag. Forms a silver mirror as non charged = solid

#3
Front (Question)

What is transition metal redox potential affected by

Back (Answer)

Ligand pH

#4
Front (Question)

How does pH affect redox potential

Back (Answer)

Alkaline = Easier to oxidise a transition metal = higher redox potential Acidic = Easier to reduce a transition metal = lower redox potential

#5
Front (Question)

How does ligands affect redox potential

Back (Answer)

Higher oxidation state = better oxidising agent = higher redox potential Lower oxidation state = better reducing agent = lower redox potential

#6
Front (Question)

Reducing agent in the reduction of ammonium vanadate

Back (Answer)

Zinc

#7
Front (Question)

Conditions in the reduction of ammonium vanadate

Back (Answer)

Acidic conditions (HCl)

#8
Front (Question)

Species present and colour of Vandium successive reductions P.s. You Better Get Vandium

Back (Answer)

V(+5) = VO2+ = Yellow V(+4) = VO^2+ = Blue V(+3) = V3+ = Green V(+2) = V2+ = Violet

#9
Front (Question)

Overall equation of reacting potassium manganate (VII) with iron

Back (Answer)

5Fe2+ + MnO4- + 8H+ → 5Fe3+ + Mn2+ + 4H2O

#10
Front (Question)

Oxidising agent and acid of potassium manganate reactions

Back (Answer)

MnO4- Dilute sulfuric acid

#11
Front (Question)

Unsuitable acids in potassium manganate

Back (Answer)

HCl = MnO4- would oxidise 2Cl- to Cl2 and affect the volume of KMnO4 required in the reaction Conc sulfuric / nitric acid = Act as oxidising agents so affect the volume of KMnO4 required in the reaction Ethanoic acid = Weak acid and not provide enough H+ atoms

#12
Front (Question)

Why is the potassium manganate self indicating

Back (Answer)

MnO4- is a purple colour but forms colourless Mn2+ so when a pink colour remains, end point is reached.

#13
Front (Question)

Overall reaction of C2O42-

Back (Answer)

5C2O42- + 2MnO4- + 16H+ → 10CO2 + 2Mn2+ + 8H2O

#14
Front (Question)

Why is the reaction between MnO4- and C2O42- slow?

Back (Answer)

Both negative ions so repel each other

#15
Front (Question)

Why is the reaction between MnO4- and C2O42- have an autocatalysis?

Back (Answer)

Mn2+ formed as an intermediate which is positive and speeds up the reaction

#16
Front (Question)

What is the strongest vanadium reducing agent

Back (Answer)

V(2+)

#17
Front (Question)

How is VO2+ (blue) → V3+ (green)

Back (Answer)

VO2+ + 2H+ + e− → V3+ + H2O