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Unit 1-Reaction Quantities

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Total cards: 16•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

What is meant by the gram formula mass (GFM)?

Back (Answer)

The mass of one mole of a substance

#2
Front (Question)

How do you calculate the GFM of a compound?

Back (Answer)

Add together the relative atomic masses of all atoms in the formula

#3
Front (Question)

What is the GFM of CO2?

Back (Answer)

12 + (2 × 16) = 44 g mol⁻¹

#4
Front (Question)

What is the formula linking mass, moles and GFM?

Back (Answer)

Number of moles = mass ÷ GFM

#5
Front (Question)

How many moles are in 25 g of CaCO₃ (GFM = 100)?

Back (Answer)

n = m ÷ GFM 25 ÷ 100 n = 0.25 moles

#6
Front (Question)

What is the mass of 0.25 moles of butane (C4H10) GFM is 58

Back (Answer)

mass = number of moles x GFM mass = 0.25 x 58 mass = 14.5 g

#7
Front (Question)

What is the formula linking concentration, moles and volume?

Back (Answer)

number of moles = concentration × volume

#8
Front (Question)

How many moles are in 400 cm³ of 0.2 mol l⁻¹ NaOH?

Back (Answer)

Number of moles = concentration x volume Convert volume to litres by dividing by 1000 n = 0.2 x 0.4 n= 0.08 moles

#9
Front (Question)

What is the concentration when 0.75 moles is dissolved in 500 cm-3?

Back (Answer)

Concentration = number of moles ÷ volume. Convert volume into litres by dividing by 1000. c = 0.75 ÷ 0.5 = 1.5 mol l-1 Concentration = 1.5 mol l-1

#10
Front (Question)

What volume is needed for 1.2 moles of solute in a 0.6 mol l-1 solution?

Back (Answer)

Volume = number of moles ÷ concentration V = 1.2 ÷ 0.6 = 2.0 l

#11
Front (Question)

What mass of magnesium is needed to produce 0.8 g of hydrogen gas? Mg + 2HCl → MgCl2 + H2

Back (Answer)

Moles of hydrogen = m ÷ GFM n = 0.8/2 = 0.4 moles ratio is 1:1 therefore also 0.4 moles of magnesium Mass of magnesium = n x GFM m = 0.4 x 24.5 m = 9.8g

#12
Front (Question)

What mass of oxygen is produce when 85g of hydrogen gas decomposes? 2H2O2 → 2H2O + O2

Back (Answer)

Moles of hydrogen peroxide = m ÷ GFM n = 85/34 = 2.5 moles ratio is 2:1 therefore 1.25 moles of oxygen Mass of oxygen = n x GFM m = 1.25 x 32 m = 40 g

#13
Front (Question)

What mass of copper(II) sulfate is produced when 8.0 g of copper(II) oxide reacts completely? CuO + H2SO4 → CuSO4 + H2O

Back (Answer)

Moles of CuO = m ÷ GFM n = 8/79.5 = 0.1 moles ratio is 1:1 therefore also 0.1 moles of CuSO4 Mass of copper sulfate = n x GFM m = 0.1 x 159.5 m =15.95 g

#14
Front (Question)

How do you calculate percentage by mass?

Back (Answer)

% by mass = (mass of element in 1 mole ÷ GFM) × 100

#15
Front (Question)

What is the % of magnesium in magnesium oxide (MgO)?

Back (Answer)

Mg has GFM of 24 g mol-1 . MgO has GFM = 40 g mol-1 % by mass = (24 ÷ 40) × 100 = 60%

#16
Front (Question)

What is the % of nitrogen in ammonium nitrate (NH4NO3)?

Back (Answer)

8N has GFM of 14 g mol-1 . There are two nitrogen in compound. (NH4NO3) has GFM = 80 g mol-1 % by mass = (24 ÷ 80) × 100 = 35%