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Heterogeneous Solutions

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

Gravimetric analysis

Back (Answer)

• ) preparation of analyte solution • ) precipitation • ) digestion of the precipitate • ) filtration and washing of the precipitate • ) drying and weighing of the precipitate • ) determination of amount of analyte present

#2
Front (Question)

Properties of precipitates and precipitants

Back (Answer)

Specificity and Selectivity- should be specific and react with only one chemical species

#3
Front (Question)

Important points of gravimetric analysis

Back (Answer)

Ease of recovery of analyte, particle size, colloidal and crystalline suspensions, factors determining particle size

#4
Front (Question)

Factors determining particle size

Back (Answer)

Precipitate solubility (S) & solute concentration (Q) determine particle size which is related to a property for he system called relative supersaturation

#5
Front (Question)

Relative supersaturation (rs)

Back (Answer)

Q-S/S = relative supersaturation When rs is large = colloidal When rs is small = crystalline

#6
Front (Question)

Experimental conditions

Back (Answer)

Should be chosen to minimize Q and maximize S

#7
Front (Question)

Mechanism of precipitate formation

Back (Answer)

Nucleatuon & particle growth

#8
Front (Question)

Nucleation

Back (Answer)

A small number of particles join together to produce a small solid, which may then grow further

#9
Front (Question)

Solubility

Back (Answer)

Defined as the number of grams of solute necessary to form a saturated solution in one kilogram of water

#10
Front (Question)

Fundamental rule of solubility

Back (Answer)

Like dissolves like

#11
Front (Question)

Heat of dissociation

Back (Answer)

The change in enthalpy that accompanies the formation of a solution

#12
Front (Question)

Factors influencing dissolution

Back (Answer)

• ) structure • ) pressure • ) temperature

#13
Front (Question)

Structure

Back (Answer)

Solubility increases if both solute and solvent have similar polarities

#14
Front (Question)

Pressure

Back (Answer)

Pressure exerts a remarkable effect on only gasses, the influence of pressure on solubility of gases is best expressed by Henry’s Law

#15
Front (Question)

Henry’s Law

Back (Answer)

In the absence of chemical reaction between the solute and the solvent, the quantity of gases dissolved in a solution is directly proportional to the pressure of the gas above the solution

#16
Front (Question)

Temperature

Back (Answer)

Dissolution of solids occurs more rapidly at higher temps The solubility of gas and liquid decrease with temperature

#17
Front (Question)

Solubility product constant (Ksp)

Back (Answer)

Equilibrium expression for equilibrium that exists between the solute and its ions in a saturated solution of slightly soluble ionic compound

#18
Front (Question)

Solubility product constant for PbI2

Back (Answer)

Ksp = [Pb^2+][I^-]^2 The equilibrium is independent of the amount of undissolved solute present

#19
Front (Question)

Precipitation titrations C- analyte with the concentration Mc-, with AgNO3

Back (Answer)

Preequivalence points Equivalence point Postequivalence points

#20
Front (Question)

Preequivalence points Ag+ + C- -> AgC, Ksp = [Ag+][C-]

Back (Answer)

Up to equivalence point, C- will be present in excess. Two steps are required to calculate the preequivalence point concentration of [C-].

#21
Front (Question)

Preequivalence points Ag+ + C- -> AgC, Ksp = [Ag+][C-]

Back (Answer)

[C-] = ((Vc•Mc)-(Vag•Mag)/Vc + Vag) + Ksp/[C-]

#22
Front (Question)

Correction factor

Back (Answer)

= [C-] = [Ag+] = Ksp/ ([Ag]/[C-]) Not needed if solution is very dilute or very near equivalence point

#23
Front (Question)

Equivalence point

Back (Answer)

[Ag+] = [C-] = (Ksp)^1/2

#24
Front (Question)

Post equivalence point

Back (Answer)

[Ag+] = (((VAg•MAg)-(Va-•Mac-))/ Vc- + Vag) + Ksp/[Ag]