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Mass calculations

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Total cards: 18•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (18)

#1
Front (Question)

Calculating Empirical Formula

Back (Answer)

Steps: 1. Find the mass of each element. 2. Divide by the relative atomic mass (Ar). 3. Divide all results by the smallest number. 4. Write the ratio as the empirical formula.

#2
Front (Question)

Relative Formula Mass (Mr)

Back (Answer)

Relative Formula Mass (Mr): Sum of the relative atomic masses of all atoms in a compound. Example: MrofH2O=(2×1)+16=18

#3
Front (Question)

Empirical vs Molecular Formula

Back (Answer)

Empirical Formula: Simplest whole-number ratio of atoms in a compound. Molecular Formula: Actual number of atoms in one molecule of a compound. Example: CH2O O (Empirical) vs C6H12O6 (Molecular)

#4
Front (Question)

Deduce Empirical Formula from Molecular Formula

Back (Answer)

Example: Molecular Formula C4H10 → Empirical Formula = C2H5 (Divide by 2).

#5
Front (Question)

Law of Conservation of Mass (Closed System)

Back (Answer)

Definition: Mass is conserved in a reaction; mass of reactants = mass of products.

#6
Front (Question)

Deduce Molecular Formula from Empirical Formula

Back (Answer)

Steps: 1. Find the Mr of the empirical formula. 2. Divide the relative molecular mass by the empirical formula mass. 3. Multiply the subscripts in the empirical formula by this number.

#7
Front (Question)

Experiment to Determine Empirical Formula

Back (Answer)

Method: 1. Heat a metal (e.g., magnesium) in excess oxygen. 2. Measure the mass before and after. 3. Use mass data to calculate the empirical formula (mass of metal and oxygen).

#8
Front (Question)

Law of Conservation of Mass (Non-Enclosed System)

Back (Answer)

Non-Enclosed System: Mass may appear to change due to gas release or absorption (e.g., burning wood, CO₂ released).

#9
Front (Question)

Number of Particles from Moles

Back (Answer)

Numberofparticles=Moles×6.02×10^23

#10
Front (Question)

Moles from Mass

Back (Answer)

Formula; Moles = Mass(g) —————– Relative Formula Mass(Mr)

#11
Front (Question)

Calculating Mass of Product from Reactant

Back (Answer)

Steps: 1. Write the balanced equation. 2. Find the moles of reactant. 3. Use mole ratio to find moles of product. 4. Convert moles of product to mass.

#12
Front (Question)

The Mole

Back (Answer)

Definition: A mole is: 6.02×10^23 particles of a substance (Avogadro’s number). Molar Mass: Mass of one mole of a substance in grams = Mr (e.g., 1 mole of H₂O = 18g).

#13
Front (Question)

Calculating Mass of Reactant from Product

Back (Answer)

Steps: 1. Write the balanced equation. 2. Find the moles of product. 3. Use mole ratio to find moles of reactant. 4. Convert moles of reactant to mass.

#14
Front (Question)

Concentration of Solution (g/dm³)

Back (Answer)

Formula: Concentration(g/dm^3)= mass of solute(g) ————————– Volume of solution(dm^3)

#15
Front (Question)

Mass from Moles

Back (Answer)

Mass(g)=Moles×Mr

#16
Front (Question)

Moles from Number of Particles

Back (Answer)

6.02 x 10^23

#17
Front (Question)

Mass of Product and Limiting Reactants

Back (Answer)

Limiting Reactant: The reactant that is used up first, controlling the amount of product. Mass of Product: Depends on the amount of limiting reactant.

#18
Front (Question)

Deducing Balanced Equation

Back (Answer)

Steps: Find the moles of each substance. Simplify the mole ratio. Write the balanced equation based on this ratio.