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Formula mass

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卡片总数: 7内容版本: v4公开卡包更新时间: 8/1/2026

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#1
正面 (问题)

What is the relative atomic mass? (Ar) Where is it on a periodic table element card?

背面 (解答)

A way of saying how heavy an atom is compared with the mass of carbon -12. It is just the same as the mass number, the number on the top of the two next to the symbol. (the bigger number)

#2
正面 (问题)

What is the relative formula mass? (Mr)

背面 (解答)

All of the relative atomic masses in a molecule added together

#3
正面 (问题)

What is one mole of a substance = to?

背面 (解答)

its Mr in grams

#4
正面 (问题)

What is the formula for Mass, Formula mass and moles?

背面 (解答)

Number of moles = Mass (g of element or compound) ————————————————– Mr (of element or compound formula mass) Moles = mass over Mr

#5
正面 (问题)

How do you calculate the %mass of an element in a compound? (formula?)

背面 (解答)

Percentage mass of an element in a compound = Ar x no. of atoms of the element (O2= 16x2= 32) ———————————————————————- Mr (of the whole compound) (H2O= 18) X100 Ar divided by Mr X100

#6
正面 (问题)

What are the steps for finding the empirical formula? (4)

背面 (解答)

• List all the elements in the compound • Underneath, write their experimental masses or percentages • Divide each mass or percentage by the Ar of that element • Turn those numbers into a ratio by dividing them by a common factor, so they are low, e.g (Fe=8, O=12 so make that Fe=2, O=3 by dividing by 4) • With the ratio in its simplest form you have the empirical formula, so with Fe=2, O=3, the empirical formula is Fe2O3 (little 2s and 3s)

#7
正面 (问题)

How do you find out how much of a reactant was in the experiment? (When you know the final weight of one of the products) Steps… (3)

背面 (解答)

• Write out the balanced equation • Work out the Mr, just for the sections you want • Divide to get one gram, then multiply to get all the grams…. 48g of Mg …..reacts to give ……80g of MgO (divide to get 1g of Mg, /by 48) 1g of Mg ….. recats to get …. 80/48 of MgO (if you want 60g of Mg to react you x by 60) 60g of Mg ….. recats to get ….. 100g of MgO