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Thermodynamics

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Total cards: 15•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

define enthalpy change of formation

Back (Answer)

The standard enthalpy change of formation of a compound is the energy transferred when 1 mole of the compound is formed from its elements under standard conditions (298K and 100kpa), all reactants and products being in their standard states

#2
Front (Question)

define enthalpy of atomisation

Back (Answer)

The enthalpy of atomisation of an element is the enthalpy change when 1 mole of gaseous atoms is formed from the element in its standard state

#3
Front (Question)

define bond dissociation enthalpy (bond energy)

Back (Answer)

The bond dissociation enthalpy is the standard molar enthalpy change when one mole of a covalent bond is broken into two gaseous atoms (or free radicals)

#4
Front (Question)

define enthalpy of sublimation

Back (Answer)

The enthalpy change for a solid metal turning to gaseous atoms can also be called the Enthalpy of sublimation and will numerically be the same as the enthalpy of atomisation

#5
Front (Question)

define first ionisation ethalpy

Back (Answer)

The first ionisation enthalpy is the enthalpy change required to remove 1 mole of electrons from 1 mole of gaseous atoms to form 1 mole of gaseous ions with a +1 charge

#6
Front (Question)

define second ionisation enthalpy

Back (Answer)

The second ionisation enthalpy is the enthalpy change to remove 1 mole of electrons from one mole of gaseous 1+ ions to produces one mole of gaseous 2+ ions.

#7
Front (Question)

define first electron affinity

Back (Answer)

The first electron affinity is the enthalpy change that occurs when 1 mole of gaseous atoms gain 1 mole of electrons to form 1 mole of gaseous ions with a –1 charge The first electron affinity is exothermic for atoms that normally form negative ions. This is because the ion is more stable than the atom, and there is an attraction between the nucleus and the electron

#8
Front (Question)

define second electron affinity

Back (Answer)

The second electron affinity is the enthalpy change when one mole of gaseous 1- ions gains one electron per ion to produce gaseous 2- ions. The second electron affinity for oxygen is endothermic because it take energy to overcome the repulsive force between the negative ion and the electron.

#9
Front (Question)

define enthalpy of lattice formation

Back (Answer)

The enthalpy of lattice formation is the standard enthalpy change when 1 mole of an ionic crystal lattice is formed from its constituent ions in gaseous form.

#10
Front (Question)

define enthalpy of lattice dissocation

Back (Answer)

The enthalpy of lattice dissociation is the standard enthalpy change when 1 mole of an ionic crystal lattice form is separated into its constituent ions in gaseous form

#11
Front (Question)

define enthalpy of hydration

Back (Answer)

Enthalpy change when one mole of gaseous ions become aqueous ions. This always gives out energy (exothermic, -ve) because bonds are made between the ions and the water molecules.

#12
Front (Question)

define enthalpy of solution

Back (Answer)

The enthalpy of solution is the standard enthalpy change when one mole of an ionic solid dissolves in a large enough amount of water to ensure that the dissolved ions are well separated and do not interact with one another

#13
Front (Question)

why do we use born Haber cycles?

Back (Answer)

The lattice enthalpy cannot be determined directly. We calculate it indirectly by making use of changes for which data are available and link them together in an enthalpy cycle the Born-Haber cycle

#14
Front (Question)

what do you do if the question gives you the enthalpy of lattice dissociation instead of formation?

Back (Answer)

This Born Haber cycle has been constructed using a lattice enthalpy of formation. Sometimes questions will give the enthalpy of lattice dissociation which has the opposite sign and the arrow points in the opposite direction. This changes the calculation.

#15
Front (Question)

write the formula for calculating the lattice enthalpy of formation

Back (Answer)

ΔfH =ΔatH (Na) + ΔIEH(Na)+ ΔatH(Cl) + ΔeaH(Cl) + ΔLattH