返回卡包市场

22- Enthalpy and Entropy

暂无描述。系统推荐的高质量记忆内容,适合每天坚持背诵学习。

卡片总数: 24内容版本: v4公开卡包更新时间: 8/1/2026

卡片预览 (24 张)

#1
正面 (问题)

What is lattice enthalpy?

背面 (解答)

The enthalpy change when 1 mole of a solid ionic compound is formed from its gaseous ions under standard conditions. Always exothermic (ΔH < 0).

#2
正面 (问题)

Why is a Born-Haber cycle used to find lattice enthalpy?

背面 (解答)

Because it’s impossible to directly combine gaseous ions in the lab to form a solid lattice. Instead, we use Hess’s Law with measurable enthalpy changes.

#3
正面 (问题)

List the enthalpy changes in a Born-Haber cycle for NaCl.

背面 (解答)

Atomisation of Na(s) → Na(g) Atomisation of ½Cl₂(g) → Cl(g) Ionisation of Na(g) → Na⁺(g) + e⁻ Electron affinity: Cl(g) + e⁻ → Cl⁻(g) Lattice formation: Na⁺(g) + Cl⁻(g) → NaCl(s)

#4
正面 (问题)

Compare first and second electron affinity of oxygen.

背面 (解答)

First EA: O(g) + e⁻ → O⁻(g), exothermic (–141 kJ/mol) Second EA: O⁻(g) + e⁻ → O²⁻(g), endothermic (+790 kJ/mol) → Adding e⁻ to a negative ion requires energy (repulsion).

#5
正面 (问题)

How are lattice enthalpy, hydration, and solution enthalpies related?

背面 (解答)

The hydration enthalpy is the enthalpy change when 1 mole of gaseous ions dissolve in sufficient water to give an infinitely dilute solution. Hydration enthalpies are always negative. The enthalpy of solution is then equal to the enthalpy of hydration minus the lattice energy Ionic solid → gaseous ions → aqueous ions

#6
正面 (问题)

How do ionic charge and size affect lattice enthalpy?

背面 (解答)

Higher charge → stronger attraction → more exothermic LE Smaller ions → closer together → more exothermic LE

#7
正面 (问题)

What is entropy?

背面 (解答)

A measure of disorder or energy dispersal in a system. Units: J K⁻¹ mol⁻¹ Gases > liquids > solids in entropy.

#8
正面 (问题)

Predict ΔS for: a) H₂O(g) → H₂O(l) b) CaCO₃(s) → CaO(s) + CO₂(g)

背面 (解答)

a) Negative (gas → liquid = more order) b) Positive (solid → solid + gas = more disorder)

#9
正面 (问题)

How do you calculate standard entropy change?

背面 (解答)

ΔS° = ΣS°(products) – ΣS°(reactants) Use data book values in J K⁻¹ mol⁻¹

#10
正面 (问题)

Write the Gibbs equation.

背面 (解答)

ΔG = ΔH – TΔS ΔG < 0 → reaction is feasible (spontaneous) T must be in Kelvin Ensure units match: ΔH in kJ/mol, ΔS in kJ/K/mol

#11
正面 (问题)

When is a reaction feasible at all temperatures?

背面 (解答)

Always feasible: ΔH < 0 and ΔS > 0 Never feasible: ΔH > 0 and ΔS < 0 Temp-dependent: ΔH < 0, ΔS < 0 → feasible at low T ΔH > 0, ΔS > 0 → feasible at high T

#12
正面 (问题)

If ΔG < 0, why might a reaction not happen?

背面 (解答)

High activation energy → slow rate (e.g., H₂O₂ decomposition). ΔG predicts thermodynamic feasibility, not speed.

#13
正面 (问题)

KCl(s) → K⁺(aq) + Cl⁻(aq), ΔH = +16 kJ/mol, ΔS = +77 J/K/mol. Is it feasible at 25°C?

背面 (解答)

ΔG = 16 – (298 × 0.077) = 16 – 22.9 = –6.9 kJ/mol → Yes, feasible (endothermic but entropy-driven).

#14
正面 (问题)

How do you find the minimum T for a reaction to be feasible?

背面 (解答)

Set ΔG = 0 → T = ΔH / ΔS (Ensure ΔH and ΔS same sign, and units consistent)

#15
正面 (问题)

Why are some ionic compounds liquids at room temperature?

背面 (解答)

Large, irregularly shaped ions (e.g., [EMIM]⁺) can’t pack efficiently into a lattice → low melting point.

#16
正面 (问题)

What does the terms Feasible and Spontaneous mean?

背面 (解答)

Feasible tends to be used to describe reactions which are energetically favourable, so reactions that should go Spontaneous tends to be used to describe reactions that go of their own accord

#17
正面 (问题)

What is the Standard Enthalpy Change of Formation?

背面 (解答)

Definition: The enthalpy change when 1 mole of a compound is formed from its elements in their standard states under standard conditions (298 K, 100 kPa). Exo/Endo: Usually exothermic (e.g., ΔₐH°(NaCl) = –411 kJ mol⁻¹), but can be endothermic for unstable compounds.

#18
正面 (问题)

What is the Lattice Enthalpy?

背面 (解答)

Symbol: ΔₗₑH° or ΔₗₐₜH° Definition: The enthalpy change when 1 mole of a solid ionic compound is formed from its gaseous ions under standard conditions. Exo/Endo: Always exothermic (e.g., ΔₗₑH°(NaCl) = –788 kJ mol⁻¹).

#19
正面 (问题)

What is the Standard Enthalpy Change of Atomisation?

背面 (解答)

Symbol: ΔₐₜH° Definition: The enthalpy change when 1 mole of gaseous atoms is formed from an element in its standard state under standard conditions. Exo/Endo: Always endothermic (bonds broken). E.g., Na(s) → Na(g), ΔₐₜH° = +108 kJ mol⁻¹ E.g., ½Cl₂(g) → Cl(g), ΔₐₜH° = +121 kJ mol⁻¹

#20
正面 (问题)

What is the First Ionisation Energy?

背面 (解答)

Symbol: IE₁ or ΔᵢₑH° Definition: The enthalpy change to remove 1 mole of electrons from 1 mole of gaseous atoms to form 1 mole of gaseous 1+ ions. Exo/Endo: Always endothermic (e.g., Na(g) → Na⁺(g) + e⁻, Δ = +496 kJ mol⁻¹)

#21
正面 (问题)

What are the Second (and Successive) Ionisation Energy?

背面 (解答)

Symbol: IE₂, IE₃, etc. Definition: Energy to remove further electrons from gaseous ions (e.g., Mg⁺(g) → Mg²⁺(g) + e⁻). Exo/Endo: Always endothermic (and larger than previous IE).

#22
正面 (问题)

What is the First Electron Affinity

背面 (解答)

Symbol: EA₁ or ΔₑₐH° Definition: The enthalpy change when 1 mole of electrons is added to 1 mole of gaseous atoms to form 1 mole of gaseous 1– ions. Exo/Endo: Usually exothermic (e.g., Cl(g) + e⁻ → Cl⁻(g), Δ = –346 kJ mol⁻¹)

#23
正面 (问题)

What is the Second (and Successive) Electron Affinity?

背面 (解答)

Symbol: EA₂, etc. Definition: Adding an electron to a negative ion (e.g., O⁻(g) + e⁻ → O²⁻(g)). Exo/Endo: Always endothermic due to repulsion (e.g., EA₂(O) = +790 kJ mol⁻¹)

#24
正面 (问题)

What is the Enthalpy Change of Solution

背面 (解答)

Symbol: ΔₛₒₗH° Definition: The enthalpy change when 1 mole of solute dissolves in excess water to form an infinitely dilute solution. Exo/Endo: Can be exothermic (e.g., NaOH) or endothermic (e.g., KCl, Δ = +16 kJ mol⁻¹)