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Alkanes

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卡片总数: 13内容版本: v4公开卡包更新时间: 8/1/2026

卡片预览 (13 张)

#1
正面 (问题)

what are structural isomers/

背面 (解答)

molecules with the same molecular formula but a different structural formula

#2
正面 (问题)

what shape are all alkanes and why?

背面 (解答)

tetrahedral- they have 4 bonded pairs of electrons and no lone pairs

#3
正面 (问题)

how does boiling point of alkanes change with branching?

背面 (解答)

more branches = fewer points of contact= weaker IDD interaction= lower bpt

#4
正面 (问题)

write an equation for combustion of C2H6 with excess o2

背面 (解答)

C2H6 + 3.5O2 -> 2CO2 + 3H20

#5
正面 (问题)

write an equation for combustion of C2H6 with limited O2, forming a toxic gas

背面 (解答)

C2H6 + 2.5 O2 -> 2CO + 3H20

#6
正面 (问题)

write an equation for combustion of C2H6 with limited O2 forming a black solid

背面 (解答)

C2H6 + 1.5 O2 -> 2C + 3H2O

#7
正面 (问题)

what is a sigma bond?

背面 (解答)

head on overlap of 2 atomic orbitals directly in a line between the 2 bonded atoms

#8
正面 (问题)

what condition is necessary for an alkane to react with a halogen?

背面 (解答)

uv light

#9
正面 (问题)

give the overall equation for the reaction between propane and bromine to form bromopropane

背面 (解答)

C3H8 + Br2 -> C3H7Br + HBr

#10
正面 (问题)

what is a radical?

背面 (解答)

a species with an unpaired electron

#11
正面 (问题)

what type of bond breaking is shown in radical substitution?

背面 (解答)

homolytic fission- a covalent bond breaking with one of the bonded electrons going to each atom forming 2 radicals

#12
正面 (问题)

give the full mechanism for the reaction between methane and chlorine + name.

背面 (解答)

name: radical substitution initiation: Cl2 -> 2Cl. (.= radical) propagation: Cl. + CH4 -> C.H3 + HCl C.H3 + Cl2 -> CH3Cl + Cl. termination: Cl. + Cl. -> Cl2 Cl. + C.H3 -> CH3Cl C.H3 + C.H3 -> C2H6

#13
正面 (问题)

give 2 problems with radical substitution

背面 (解答)

1) further substitution: CH3Cl could react with CL. again multiple times, and hydrogens could keep getting substituted for chlorine. 2) mixture of isomers formed eg: C4H10 + Cl2 -> CH3CH2CH2CH2Cl or CH3CH(Cl)CH2CH3