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5.1, Kp, Ka, Kw ect.

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

What is the definition of an equilibrium law?

Back (Answer)

The equilibrium law states that for the equilibrium aA + bB ⇔ C + dD Kc = [C]c[D]d/[A]a[B]b

#2
Front (Question)

What is the definition of a homogeneous equilibrium?

Back (Answer)

A homogeneous equilibrium is an equilibrium in which all the species making up the reactants and products are in the same physical state.

#3
Front (Question)

What is the definition of a heterogeneous equilibrium?

Back (Answer)

is an equilibrium in which species making up the reactants and products are in different physical states.

#4
Front (Question)

How are the three meanings of K presented differently?

Back (Answer)

The equilibrium constant is represented by a capital K, followed by a subscript letter to indicate which equilibrium constant you are referring to a lower case k represents the rate constant and K is on its own is the symbol for potassium.

#5
Front (Question)

What would Kc, and it’s units be for the reaction 2SO2 (g) + O2 (g) ⇔ 2SO3(g) ?

Back (Answer)

• Kc = [SO2(g)]2/ [SO2(g)]2 [O2(g)] • Units (moldm-3)2/ (moldm-3)3 = dm3mol-1

#6
Front (Question)

What needs to be known to determine concentrations at equilibrium?

Back (Answer)

To determine a value of Kc, the concentration of reactants and products need to be known. Chemists determine the concentrations in a number of ways including a titration and using a colorimeter.

#7
Front (Question)

What are the drawbacks of using titrations to determine concentrations at equilibrium?

Back (Answer)

• Titrating a reactant or product against a known concentration will show how much of the reactant or product os present. • However the reactant or product has to be removed from the reaction mixture, and this will alter the position of equilibrium. • Other substances may also be present, affecting the results (catalysts).

#8
Front (Question)

What can monitor the concentrations of product molecules throughout reactions to determine the value of Kc?

Back (Answer)

A colorimeter can be used to monitor the concentrations of a reactant or product throughout. This works because coloured substances alter the amount of light that can pass through.

#9
Front (Question)

Calculating unknown equilibrium concentrations; What can you tell from a balanced equation?

Back (Answer)

• the reacting quantities needed to prepare a required quantity of a product • the quantities of products formed by reacting other known quantities of reactants.

#10
Front (Question)

What are the steps involved in calculating Kc from unknown equilibrium concentrations?

Back (Answer)

• Find the concentrations of all three components in the equilibrium mixture • Work out the equilibrium amounts of the reacting molecules. • You can use the balanced equation and stiochiochemistry to find out the moles of a reactant used a product formed. • Finally, convert the amounts to concentration. Follow these steps on the example on page 25.

#11
Front (Question)

What are the steps of calculating Kc from equilibrium concentrations?

Back (Answer)

• Calculate the moles at equilibrium by giving the moles at equilibrium by the volume of substance or container. • Write the expression for Kc and work out the units. Then calculate Kc under these conditions. Example on pg 24

#12
Front (Question)

If you are given equilibrium amounts in moles and you know the total volume, what must you calculate first?

Back (Answer)

The concentrations. concentrations = no. moles / volume in dm3

#13
Front (Question)

What is affected by an equilibrium being heterozygous, instead of homozygous?

Back (Answer)

When a heterogeneous equilibrium is present, molar concentrations for solids and pure liquids do not change because their volume remains constant. This means that the expression for Kc changes: • the concentrations of solid substances are not included in the expression • the concentrations of pure liquids are not included in te expression

#14
Front (Question)

What is the expression for Kc for the reaction P4 (s)+ 5O2 (g) ⇔ P4O10 (s)?

Back (Answer)

Kc = [O2]5

#15
Front (Question)

What is a mole fraction?

Back (Answer)

The mole fraction of a substance is a measure of how much of a given substance is present in a reaction mixture.

#16
Front (Question)

What is the partial pressure?

Back (Answer)

The partial pressure of a substance is the pressure an individual gaseous substance would exert if it occupied a whole reaction vessel on its own.

#17
Front (Question)

What symbol is given to the mole fraction?

Back (Answer)

It is given the symbol X.

#18
Front (Question)

How is the mole fraction of a substance calculated?

Back (Answer)

mole fraction, XA = number of moles of substance A / total number of moles of all substances

#19
Front (Question)

What is the pressure of any reaction mixture involving gases within a sealed vessel the sum of?

Back (Answer)

The pressure of any reaction mixture involving gases within a sealed vessel is effectively the sum of being exerted by each of the gaseous substances involved. The amount of pressure being exerted by an individual species within a reaction vessel is called the partial pressure.

#20
Front (Question)

What symbol is the partial pressure given?

Back (Answer)

partial pressure is given the symbol, P, followed by a subscript denoting the species to which is refers.

#21
Front (Question)

How do you calculate partial pressure from the total pressure?

Back (Answer)

If we know the total pressure of a reaction along with the mole fraction of a given substance, we can calculate the partial pressure of that substance. For substance A: partial pressure, PA = mole fraction x total pressure.

#22
Front (Question)

What equilibrium constant is used for reactions involving gases?

Back (Answer)

Equilibrium expressions can be written using partial pressures instead of concentrations.

#23
Front (Question)

What would the equilibrium constant, Kp, be for the reaction aA + bB ⇔ cC + dD?

Back (Answer)

kp = (pC)c (PD)d / (PA)a (PB)b

#24
Front (Question)

Back (Answer)