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Kinetics 6: Main recall

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Total cards: 23•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

Rate constants often vary with temp, many according to the Arhenius equation. • Give the eq • Define the components, giving units

Back (Answer)

KT = Aexp(-Ea/RT) • KT = rate constant, units vary • A = A-factor / pre-exponential factor* same units & dimensions as K, since exp term is dimensionless • Ea = act energy in kJ mol-1 • R = gas constant, in kJ [temp unit]-1 mol-1 (so that overall, exp term is dimensionless) • T = temp, K * A is the collision rate per unit reactant concentration. A is also the rate constant at infinite temp, since 1/T = 0 when lnK = lnA. A is independent of or weakly dependent on temp

#2
Front (Question)

Range of typical values for Ea

Back (Answer)

10-200 kJ mol-1

#3
Front (Question)

Value of RT at room temp

Back (Answer)

~2.4 kJ mol-1

#4
Front (Question)

What fraction of molecules have sufficient energy to attain the transition state?

Back (Answer)

Fraction = exp(-Ea/RT) Recall RT = 2.4 kJ mol-1 at room temp

#5
Front (Question)

Gas kinetic theory • Expression for mean speed, give unit • Bimolecular collisions depend on the relative motion of the molecules. Expression for mean relative speed?

Back (Answer)

ĉ = √(8KBT/πm) in ms-1 KB is Boltzmann constant, m = particle mass in kg ĉ = √(8KBT/μ) in ms-1 Where reduced mass, μ = (mAmB/mA+mB) μ in AMU, atomic mass units

#6
Front (Question)

Define and give the eq for the steric factor.

Back (Answer)

Steric factor p is the fraction of sufficiently energetic collisions which lead to reaction p = Aexperimental/Acoll theory normally p <1, but p >1 when molecules interact over larger distances than predicted by gas kinetic theory

#7
Front (Question)

Gas kinetic theory • Expression for mean speed, give unit • Bimolecular collisions depend on the relative motion of the molecules. Expression for mean relative speed?

Back (Answer)

ĉ = √(8KBT/πm) in ms-1 KB is Boltzmann constant, m = particle mass in kg ĉ = √(8KBT/μ) in ms-1 Where reduced mass, μ = (mAmB/mA+mB) μ in AMU, atomic mass units

#8
Front (Question)

1st order rate law

Back (Answer)

r = k1st[A] d[A]/dt = -k[A]

#9
Front (Question)

integrated 1st order rate law in terms of reactant

Back (Answer)

[A]t = [A]0exp(-k1stt)

#10
Front (Question)

Produce and solve the rate law for the second order reaction A –> products.

Back (Answer)

rate law d[A]/dt = -k2nd[A]2 ∫(from [A]t to [A]0) 1/[A] d[A] = k2nd ∫(from t=t to t=0) dt 1/[A]t = k2ndt + 1/[A]0

#11
Front (Question)

Give the expression for the half-life for a first-order reaction.

Back (Answer)

t1/2 = ln2/k1st

#12
Front (Question)

Give the expression for the half-life for a second order reaction.

Back (Answer)

t1/2 = 1/(k2nd[A]0)

#13
Front (Question)

Study the reaction scheme below. What conditions are required for the pre-equilibrium hypothesis to apply?

Card front image
Back (Answer)

Rate of process 1 >> rate of process 2, such that rates of [1] and [-1] are equal (in equilibrium), and process [2] is rate-determining. pre-eq hypothesis is often useful for intermediates involving protonation or deprotonation, since these processes are usually faster than breaking/making bonds to atoms heavier than hydrogen

#14
Front (Question)

What conditions permit using the steady state approximation? Include a graph of concentration against time.

Back (Answer)

Applicable when, in a complex mechanism, a reactive intermediate reacts as soon as it’s formed, such that its concentration is assumed to be constant. Only applicable when reaction is in steady state - not in the initial or final phases. simplifies solving differential eqs since it removes the time dependence

Card back image
#15
Front (Question)

Write out the Michaelis-Menten scheme.

Back (Answer)

Card back image
#16
Front (Question)

Shown is the Michaelis-Menten scheme. Write the expression for Vmax and define it.

Card front image
Back (Answer)

Vmax = kcat[E]0 Maximum velocity which occurs when all enzyme is saturated, i.e. 0 order in [S].

#17
Front (Question)

Shown is the Michaelis-Menten scheme. • Give the expression for KM • What units does it have? • define it

Card front image
Back (Answer)

kM = (k-1 + kcat)/k1) Units of conc KM is the substrate conc which gives ha;f-maximum velocity.

#18
Front (Question)

Shown is the Michaelis-Menten scheme. Write the Michaelis-Menten equation, i.e. the expression for the velocity, V (ie rate) of reaction.

Card front image
Back (Answer)

V = (kcat[E]0[S]) / ([S] + (k-1 + kcat)/k1) = (kcat[E]0[S]) / ([S] + kM) where KM is the michaelis constant

#19
Front (Question)

What is a chain reaction?

Back (Answer)

A reaction comprised of non-linear elementary steps, which form chains in which the output of one step may be the input of an earlier step.

#20
Front (Question)

What are the general stages of a chain reaction?

Back (Answer)

• Initiation generates chain carriers • Propogation maintains chain carriers • Inhibition reduces reaction rate by destroying product (but not chain carriers) • Termination destroys chain carriers • Chain branching (sometimes): one chain carrier reacts to give 2+ carriers (results in explosion, eg combustion)

#21
Front (Question)

The thermal chain reaction H2 + Br2 –> 2HBr is well-characterised. Illustrate the stages of this reaction.

Back (Answer)

Initiation Br2 + M –> 2Br + M where M is a molecule Or photodissociation: Br2 + hv –> 2Br Propogation Br + H2 –> HBr + H H + Br2 –> HBr + Br Inhibition HBr + H –> H2 + Br Termination 2Br + M –> Br2 + M (M absorbs excess energy from new Br2 molecule, such that the Br2 doesn’t immediately fall apart)

#22
Front (Question)

What is a chain carrier?

Back (Answer)

An intermediate formed during a chain reaction, which is an input into earlier reactions, and thus propogates the reaction.

#23
Front (Question)

Define chain length. Give its expression.

Back (Answer)

The average number of times that the closed cycle of steps producing products is repeated per chain carrier. chain length, l = (overall reaction rate)/(rate of initiation)