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aromatics

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卡片总数: 15内容版本: v4公开卡包更新时间: 8/1/2026

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#1
正面 (问题)

why is c6h5ch2nh2 stronger than a benzene with no2 at the top and ch2 at the bottom

背面 (解答)

the lone pair of electrons on the n for the second one is more equally spread out which means the electron density at the n will be reduced so less electrons available (for protonation or donation) so it is less basic

#2
正面 (问题)

one use of phenyl amines is making dyes, give 3 other uses

背面 (解答)

making cationic surfactants making hair conditioner making fabric softener

#3
正面 (问题)

bond angle in benzene and cyclohexane

背面 (解答)

120 degrees in benzene, and 109 in cyclohexane

#4
正面 (问题)

explain the bonding in benzene and the shape of benzene. compare its stability with that of the hypothetical cyclohexa-1,3,5-triene. use data in your answer. (6 marks)

背面 (解答)

each carbon has 3 covalent bonds, lone electrons in the p orbitals overlap and this leads to delocalisation. This forms a ring of delocalised electrons which helps making benzene stable benzene is a planar hexagon and the c-c bonds are equall in length. stability- expected for cyclohexa is -360 but hydrog for benzene is -208 which is 152kjmol-1 less exothermic and because benzene is lower in energy than cyclo therefore it is more stable.

#5
正面 (问题)

the enthalpy of hydrogen of cyclo hexa 1,3 di ene is not exactly double that of cyclohexene, suggest a value for it and justify your value

背面 (解答)

range of -239 to -121. the double bonds are separated by one single bond, it allows some delocalisation or the overlap of p orbitals.

#6
正面 (问题)

why the crude oil product was dissolved in the minimum quantity of hot water why was the solution filtered why was the flask left to cool at room temp why was a clean cork used to compress the crystals in the funnel why did they add a little cold water (poured) through the crystals

背面 (解答)

hot water- to ensure that crystals would form upon cooling filtered- to remove any insoluble impurities flask left to cool- as the yield would be lower if warm compress crystals- so air passes through the sample not just around it cold water- to wash away soluble impurities

#7
正面 (问题)

the melting point of this sample was found to have a slightly lower mp than a data book- suggest the most likely impurity to have caused this low value and suggest an improvement to the method so a more accurate value for the mp can be obtained

背面 (解答)

water (excess water) press the sample of crystals between filter papers

#8
正面 (问题)

simply, in terms of bonding state why benzene is more stable than cyclo hexa 1,3,5 tri ene

背面 (解答)

due to delocalised electrons

#9
正面 (问题)

bond lengths in benzene and shape and stability

背面 (解答)

all roughly 140 in benzene so its not a distorted hexagon but kekules would be as the double bond c=c and single bond c-c is different All of the carbon-carbon bonds have exactly the samelengths - somewhere between single and double bonds because there are delocalized electrons above and below the plane of the ring, which makesbenzene particularly stable

#10
正面 (问题)

comparing bond lengths for benzene and kekules structure

背面 (解答)

benzene= 140 all bonds cyclohexa blah c-c= a54 cyclohexa c=c =134

#11
正面 (问题)

The hydrocarbons benzene and cyclohexene are both unsaturated compounds. Benzene normally undergoes substitution reactions, but cyclohexene normally undergoes addition reactions. (a) The molecule cyclohexatriene does not exist and is described as hypothetical. Use the following data to state and explain the stability of benzene compared with the hypothetical cyclohexatriene

背面 (解答)

benzene is more stable than cyclohexa expected hydrogenation of benzene is -360 but its actually -208 which is +152 kjmol-1 more stable= less exothermic. Because of delocalisation

#12
正面 (问题)

Explain why amine U is a weaker base than amine W.

背面 (解答)

Lone or electron pair on N No marks if reference to “lone pair on N” missing 1 Delocalised or spread into ring in U 1 Less available (to accept protons) or less able to donate (to H+ )

#13
正面 (问题)

predicting a value for cycohexa 1,3 di ene where the double bonds are closer than 1.4 di ene. why is the enthalpy of hydrogenation of it lower

背面 (解答)

if lower enthalpy of hydrogenation= more stable more energy used to break bonds as, the proximity for 1,3 has c=c closer together delocalisation for 1,3 which provides some extra stability for 1,3

#14
正面 (问题)

when writing a equation for the reaction of a di nitro to make a di phenyl amine

背面 (解答)

make sure you do [12H] bc theres 2 nitros to reduce and this also forms 4h2o not 2h2o

#15
正面 (问题)

bond angle in benzene and cyclohexane

背面 (解答)

benzene= 120 cyclohexane= 109