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Thermo Dynamics (5/8)

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Total cards: 17•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

Calorimetry and how it works

Back (Answer)

It mimics combustion

#2
Front (Question)

How is the body doing combustion reactions?

Back (Answer)

Molecules are consumed in the presence of oxygen, producing water and carbon dioxide The body derives energy from this

#3
Front (Question)

Units of heat

Back (Answer)

Joules or 4.184 Cal 1 Cal = 1000 cal = 1 kcal This is easier to see rather than thousands of calories

#4
Front (Question)

Definition of 1 cal

Back (Answer)

Amount of energy required to raise the temperature of 1 gram of water by 1 degree C

#5
Front (Question)

Equation for heat

Back (Answer)

Q= mc*Change in T

#6
Front (Question)

Specific heat capacity (c)

Back (Answer)

energy required to raise temperature of 1 gram of substance by 1 degree C

#7
Front (Question)

What is Enthalpy?

Back (Answer)

Total heat in a thermodynamic system Units= [J]

#8
Front (Question)

Enthalpy equation

Back (Answer)

H= U + P*V = Q

#9
Front (Question)

Endothermic vs. Exothermic

Back (Answer)

Exothermic= losing heat and H is - Endothermic= gaining heat and H is +

#10
Front (Question)

Bond dissociation energy

Back (Answer)

Enthalpy change associated with breaking bonds

#11
Front (Question)

Rules for adding enthalpy

Back (Answer)

• Each step must be ordered in forward reaction • Reverse sign of H when reversing order of a step • Multiply by coefficients

#12
Front (Question)

Gibbs Free energy

Back (Answer)

Energy that can be used to perform work in a reversible reaction

#13
Front (Question)

Free energy state of a system

Back (Answer)

G= H - T*S

#14
Front (Question)

Linking equilibrium constant and gibbs free energy

Back (Answer)

If Keq > 1 then G <1 = -, spontaneous If Keq < 1 then G >1 = +, non-spontaneous

#15
Front (Question)

Equilibrium constant under standard condition

Back (Answer)

G= -RT*lnKeq

#16
Front (Question)

Catalysts

Back (Answer)

Increase rate of reaction by lowering activation energy

#17
Front (Question)

Relationship between Keq and Q

Back (Answer)

When Keq=Q, equilibrium When Keq > Q, products favored When Keq < Q, reactants favored