Part 3

No description yet. This curated deck is ready for daily study.

Total cards: 10•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (10)

Front (Question)

1) NaBH4 2) H3O+

Back (Answer)

A reducing agent. It is more selective and easier to handle, but will NOT reduce carboxylic acids and esters. Will reduce aldehydes and ketones.

Front (Question)

1) Lithium Aluminum Hydride (LiAlH4 or LAH) 2) H3O+

Back (Answer)

A reducing agent. Strong and powerful. More difficult to work with. Will reduce all aldehydes, ketones, carboxylic acids, and esters.

Front (Question)

1) BH3 2) H2O2, OH-

Back (Answer)

Hydroboration BH3 adds readily to double bonds. Second step is oxidation-hydrolysis in an ANTI-markovnikov, syn orientation. In presence of peroxides will convert to alcohol.

Front (Question)

Cold, dilute KMnO4

Back (Answer)

An oxidizing agent. Produces 1,2 diols (vicinal diols). a.k.a. glycols with syn orientation.

Front (Question)

Alkene + Br2/CCL4 –> ?

Back (Answer)

Addition of halogens to double bonds is rapid. Double bond is nucleophile and attacks X2. Addition is anti, because X- attacks cyclic halonium ion in SN2 displacement.

Front (Question)

AlCl3 + X2 or acyl group –?

Back (Answer)

AlCl3 is a lewis acid. X2 in presence of lewis acid (FeCl3, FeBr3, AlCl3) produces monosubstituted products in good yield. AlCl3 + acyl groups = Friedel-Crafts Acylation. will incorporate acyl group.

Front (Question)

Zwitterion

Back (Answer)

An ion with both a positive and negative charge.

Front (Question)

Alcohol + Carboxylic acid –> ?

Back (Answer)

Makes an ester

Front (Question)

Henderson-Hasselbalch Equation

Back (Answer)

pH = pKa - log ([conjugate base]/[conjugate acid])

#10

Front (Question)

Nonpolar Amino Acids

Back (Answer)

Valine, Alanine, Isoleucine, Leucine, Proline, Phenylalanine, Glycine, and Tryptophan. non - TV PIG PAL”