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6.2.1 Amines

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Total cards: 21•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

what are amines

Back (Answer)

organic compounds derived from ammonia (NH3) where 1 or more of the hydrogen atoms has been replaced by a carbon chain or ring

#2
Front (Question)

what are aliphatic amines

Back (Answer)

where the N is attached to at least 1 straight or branched carbon chain, an alkyl chain R

#3
Front (Question)

what are aromatic amines

Back (Answer)

where the N is attached to an aromatic ring, an aryl group Ar

#4
Front (Question)

where do you find amines

Back (Answer)

commonly occur in nature and have many effects on the body- e.g. serotonin as a neurotransmitter

#5
Front (Question)

how can amines be classified

Back (Answer)

• primary: where the N has one carbon, alkyl or aryl, group attached to it, NH2 (R) • secondary: where the N has two carbons attached to it, NH (R, R’) • tertiary: where the N has 3 carbons attached to it, N (R,R’,R’’)

#6
Front (Question)

how do you name primary amines

Back (Answer)

• if the NH2 is present qat the end of a chain, can use suffix -amine to the name of the alkyl chain attached to, e.g. CH3H2NH2 would be ethylamine • if the NH2 is attached to any other carbon other than carbon-1, can use prefix amino , e.g. CH3CHNH2CH2CH3 is 2-aminobutane

#7
Front (Question)

how do you name secondary and tertiary amines

Back (Answer)

• if containing the same alkyl group, can use prefixes di- and tri-, e.g. (CH3)2NH = dimethylamine • when 3 or more different groups attached, need to name using N-linked • smaller group is N-linked of the bigger group, and ORDERED ALPHABETICALLY • e.g. CH3CH2C-N-CH3-CH2CH3 = N-ethyl-N-methylpropylamine

#8
Front (Question)

how do amines react

Back (Answer)

behave as bases, as contain a lone pair of electrons on the N:, and can accept a hydrogen (proton)

#9
Front (Question)

how do amines react with proton

Back (Answer)

form a dative covalent bond - e.g. CH3CH2-N:H2 + H+ → [CH3CH2NH3]+

#10
Front (Question)

how do amines react to form salts

Back (Answer)

act as bases and neutralise acids to make salts - a + goes on the N, and the -ve metal ion goes nearby • e.g. 2CH3-NH2 + H2SO4 → (CH3N+H3)2SO4-

#11
Front (Question)

how is a primary amine formed

Back (Answer)

haloalkane + :NH3 → ammonium halide salt + H2O • excess ammonia • ethanol as a solvent

#12
Front (Question)

why can ammonia be used to react with a haloalkane and form an amine

Back (Answer)

• has a lone pair of electrons on the :NH3 • can act as a nucleophile in a substitution reaction with haloalkane • produces an ammonium salt • add aqueous alkali to generate the amine from the salt

#13
Front (Question)

what is the 2 step mechanism of forming a primary amine

Back (Answer)

haloalkane + :NH3 → ammonium salt ammonium salt + NaOH → amine + sodium salt + H2O

#14
Front (Question)

what is the two step mechanism of the formation of propylamine from 1-chloropropane

Back (Answer)

CH3CH2CH2Cl + NH3 → CH3CH2CH2NH3+Cl- CH3CH2CH2NH3+Cl- + NaOH → CH3CH2CH2NH2 + NaOH + H2O

#15
Front (Question)

why is ethanol needed to form an amine

Back (Answer)

• acts as a solvent • prevents substitution of haloalkane by water • which would form an alcohol

#16
Front (Question)

why is excess ammonia needed to form an amine

Back (Answer)

prevents the further substitution of the amine group, to 2° and 3°

#17
Front (Question)

how do you form a secondary amine

Back (Answer)

primary amine + haloalkane • just a further substitution, as the N in the amine formed still contains a lone pair • continue again for tertiary

#18
Front (Question)

how would you form dipropylamine from 1-chloropropane

Back (Answer)

CH3CH2CH2Cl + CH3CH2CH2:NH2 → CH3CH2CH2-NH-CH2CH2CH3 + NaCl + H2O • still via forming the salt first, and then reacting with NaOH

#19
Front (Question)

what is an aromatic amine

Back (Answer)

benzene ring with at least one N attached, e.g. NH2

#20
Front (Question)

how do you form an aromatic amine

Back (Answer)

via reduction of nitrobenzene: 1) nitrobenzene is heated under reflux with tin and conc. hydrochloric acid 2) forms the ammonium salt phenylammonium chloride 3) the salt is then reacted with excess NaOH, to form the aromatic amine phenylamine

#21
Front (Question)

what is the equation for formation of phenylamine

Back (Answer)

⌬-NO2 + 6[H] → ⌬-NH2 + 2H2O • with Sn/conc. HCl on arrow as reducing agents • and excess NaOH(aq) on bottom