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[Part 3]- C6- electrolysis💧

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

What are aqueous solutions ? Hint: _____ molecules ionise, forming what ions? Hint: hydroxide

Back (Answer)

• aqueous solutions are dissolved in water- meaning they form when substances are dissolved in water • and water molecules ionise/dissociate [split], forming hydrogen ion and hydroxide ions.

#2
Front (Question)

What can you tell me about the formula of the copper sulfate solution, during electrolysis ? [of an aqueous solution]

Back (Answer)

• copper sulfate solution, has the formula CuSO4 (aq)- containing the copper ion: CU^2+ and the sulfate ion: SO4^2- • because it’s dissolved in water, the hydrogen ion H^+ and the hydroxide ion OH^- needs to be considered.

#3
Front (Question)

During the electrolysis of copper sulfate solution [an aqueous solution], what’s attracted to the cathode ? Hint: rule- reactivity of hydrogen

Back (Answer)

• the copper sulfate solution, contains two positive ions that would be attracted to the cathode. • ; the rule, is that hydrogen is (only) produced at the cathode, if the metal is more reactive than hydrogen. • and because copper is less reactive than hydrogen, copper will be produced at the cathode.

#4
Front (Question)

During the electrolysis of copper sulfate solution [an aqueous solution], what’s attracted to the anode ? Hint: why

Back (Answer)

• and at the anode, oxygen gas is made- [because oxygen is usually produced at the anode, when aqueous solutions are electrolysed]

#5
Front (Question)

Why are the electrodes inert ?

Back (Answer)

• the electrodes are inert [unreactive] because, it’s important that the electrodes don’t react, with the chemicals that are being made in electrolysis. • otherwise, the electrodes will take part in the reaction

#6
Front (Question)

What is the half-equation at the cathode, during the electrolysis of copper sulfate solution Hint: 2e

Back (Answer)

• Cu^2+ 2e^- ————-> Cu • this is a reduction reaction, as the copper ions are gaining electrons, to form copper atoms.

#7
Front (Question)

What is the half-equation at the anode, during the electrolysis of copper sulfate solution ? Hint: 4OH^- —> O2

Back (Answer)

4OH^- ———> O2 + 2H2O + 4e^- OR 4OH^- ➖ 4e^- ———-> O2 + 2H2O • four hydroxide ions react to form oxygen gas and water, using a total of four electrons in the process- therefore this is an oxidation reaction.

#8
Front (Question)

What’s the rule to use, when predicting what will be produced at the cathode ?

Back (Answer)

• ; the rule, is that hydrogen is (only) produced at the cathode, if the metal is more reactive than hydrogen.

#9
Front (Question)

What can you tell me about the formula of sodium chloride solution during electrolysis ? [of an aqueous solution] Hint:

Back (Answer)

• sodium chloride solution, has the formula: NaCl^- containing the sodium ion: Na and the chloride ion Cl^- • because it’s dissolved in water, the hydrogen ion H^+ and the hydroxide ion OH^- needs to be considered.

#10
Front (Question)

During the electrolysis of sodium chloride solution, what’s attracted to the cathode Hint: why?

Back (Answer)

• the sodium chloride solution, contains two positive ions that would be attracted to the cathode. [the sodium ion Na^+ and the hydroxide ion H^+] • ; the rule, is that hydrogen is (only) produced at the cathode, if the metal is more reactive than hydrogen. • and because sodium is more reactive than hydrogen, hydrogen gas will be produced at the cathode.

#11
Front (Question)

During the electrolysis of sodium chloride solution, what’s attracted to the anode?

Back (Answer)

• and at the anode, there are two negative ions that could be attracted to it- [the chloride ion: Cl^- and the hydroxide ion OH^-] • ; the rule for the anode is: that if the aqueous solution contains halide ions, then halogen will be produced at the anode. [otherwise it would typically be oxygen gas] • therefore at the anode, chlorine gas is made- since the sodium chloride solutions, contains a halide ion [chloride]

#12
Front (Question)

What is the half-equation at the cathode, during the electrolysis of sodium chloride solution ?

Back (Answer)

• H^+ ➕ e^- ———> H • this is a reduction reaction, as the hydrogen ion is gaining one electron, to form a hydrogen atom.

#13
Front (Question)

During the electrolysis of sodium chloride solution, what can else can you tell me about the cathode ?

Back (Answer)

• Since hydrogen atoms immediately pair up to form a hydrogen molecule [H2]- as hydrogen is a diatomic molecule, the half equation is doubled and now looks like this: • 2H^+ ➕ 2e^- ———> H2

#14
Front (Question)

What is the half-equation at the anode, during the electrolysis of sodium chloride solution ?

Back (Answer)

• Cl^- ———-> Cl + e^- • ; as chloride atoms always pair to form a double molecule, the half-equation must be doubled: • 2Cl^- ———-> Cl2 + 2e^- OR • 2Cl^- ➖ 2e^- ———-> Cl2 • this is an oxidation reaction, as chlorine loses one electron, to form a chlorine atom.

#15
Front (Question)

What’s the rule to use, when predicting what will be produced at the anode ? Hint: halide

Back (Answer)

• the rule for the anode is: that if the aqueous solution contains halide ions, then halogen will be produced at the anode. • [otherwise it would typically be oxygen gas, as the hydroxide ions would be attracted to the anode] • these halides ions are: fluoride (F −), chloride ( Cl −), bromide ( Br −), iodide ( I −) and astatide ( At −)

#16
Front (Question)

List all the halide ions [5]

Back (Answer)

• fluoride (F −) • chloride ( Cl −) • bromide ( Br −) • iodide ( I −) • astatide ( At −)

#17
Front (Question)

During the electrolysis of brine, what’s the equation for the change to electrolyte? Hint: symbols

Back (Answer)

• NaCl [aq] ——-> NaOH [aq]

#18
Front (Question)

What else can you tell me about the electrolysis of brine [sodium chloride solution] ?

Back (Answer)

• During the electrolysis of brine, hydrogen and chloride ions are removed from sodium chloride solution solution . • ; sodium and hydroxide ions are left behind in solution. • This means that sodium hydroxide is also formed during the electrolysis of sodium chloride solution.

#19
Front (Question)

Why can the products of the electrolysis of brine be used ? Hint: ions are removed

Back (Answer)

• Because hydrogen and chloride ions are removed from sodium chloride solution • and sodium hydroxide is also formed, during the electrolysis of sodium chloride solution. [because sodium and hydroxide ions are left behind in solution.] • the products of electrolysis of brine can be used

#20
Front (Question)

What are the uses for the electrolysis of brine ? 🚀🏊‍♂️🧼

Back (Answer)

• hydrogen can be used for fuel cells and rockets • chlorine can be used for bleach and swimming pools • and sodium hydroxide can be used for: making soap, and unblocking drains.

#21
Front (Question)

What is brine ?

Back (Answer)

• Brine is a solution of sodium chloride (NaCl) and water (H2O)

#22
Front (Question)

What’s a word equation, for the electrolysis of a solution ?

Back (Answer)

Water (l) electicity ⟶ Hydrogen (g)+ Oxygen (g)

#23
Front (Question)

What’s the test to show the change to the electrolyte ?

Back (Answer)

• litmus paper will turn blue at the anode

#24
Front (Question)

When writing half-equations, what is the tip you must remember ?

Back (Answer)

• when writing half -equations, if there is a positively charged ion, the electron goes before the arrow to balance the charges