Chapter 16 Reagents

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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Front (Question)

NaBH4 in MeOH with Aldehyde or Ketone

Back (Answer)

=O turns into -OH and -H. Works with both Aldehydes and Ketones.

Front (Question)

C6H5MgBr

Back (Answer)

=O turns into -OH, -C6H5 is added alongside the carbon of the carboxyl group. Works with both Aldehydes and Ketones.

Front (Question)

LiAlH4, then H2O

Back (Answer)

=O turns into -OH and -H. Works with both Aldehydes and Ketones.

Front (Question)

Ag2O, HO- (with and without acid)

Back (Answer)

the terminal hydrogen of the aldehyde component turns into an O-. Works with only Aldehydes. if with acid, turns into OH

Front (Question)

(C6H5)3P+ R-

Back (Answer)

Replaces =O with =R. Works with both Aldehydes and Ketones.

Front (Question)

H2 and Pt

Back (Answer)

=O turns into -OH and -H. Works with both Aldehydes and Ketones

Front (Question)

HO-R-OH and HA

Back (Answer)

Forms a ring where the double bond O was. (The =O turns into -O,-O that are connected with the R group) Works both Aldehydes or ketones

Front (Question)

Ag(NH3)2+

Back (Answer)

Replaces the H with O-, yields silver. Works only with Aldehydes.

Front (Question)

Hydroxylamine (HONH2)

Back (Answer)

Replace =O with =N-OH. Works with both Aldehydes and Ketones

#10

Front (Question)

Phenylhydrazine (PH-NHNH2)

Back (Answer)

Replace =O with =NNHPh. Works with both Aldehydes and Ketones

#11

Front (Question)

HNO3 +H2SO4

Back (Answer)

Replace a hydrogen with NO2, depending on the directing factor. For benzene rings.

#12

Front (Question)

C6H5NHNH2

Back (Answer)

Replace =O with =NNHPh. Works with both Aldehydes and Ketones

#13

Front (Question)

H2C:- +P(C6H5)3

Back (Answer)

Replace =O with =R (in this case CH2). Works with both Aldehydes and Ketones.

#14

Front (Question)

1)C6H5MgBr 2)NH4Cl

Back (Answer)

Replace =O with -OH, -C6H5 is added alongside the carbon of the carboxyl group. Works with both Aldehydes and Ketones.

#15

Front (Question)

H2NNH2, HO-, heat

Back (Answer)

Replace =O with hydrogens. Works with both Aldehydes and Ketones.

#16

Front (Question)

PCC or Swern

Back (Answer)

-OH is replaced with =O, hydrogen is removed. Works with 1* and 2* alcohols to give aldehydes and ketones.

#17

Front (Question)

Pyridine/CrO3

Back (Answer)

-OH is replaced with =O, hydrogen is removed. Works with 1* and 2* alcohols to give aldehydes and ketones. This is another way to write PCC

#18

Front (Question)

H2CrO4

Back (Answer)

-OH is replaced with =O, hydrogen is removed. Works with 2* alcohols to give ketones.

#19

Front (Question)

KMnO4

Back (Answer)

-OH is replaced with =O, hydrogen is removed. Works with 2* alcohols to give ketones Will also convert aldehydes to carboxylic acids (-H to -OH)

#20

Front (Question)

NaCN

Back (Answer)

Replace =O with -OH and -CN. Occurs with both Aldehydes and Ketones.

#21

Front (Question)

Primary Amine (NH2R) +HA

Back (Answer)

Replace =O with =NR. Occurs with both Aldehydes and Ketones.

#22

Front (Question)

Secondary Amine (NHR2) +HA

Back (Answer)

Replace =O with -NR2 and a double bond on more substituted carbon. Occurs with both Aldehydes and Ketones.

#23

Front (Question)

Zn/Hg/HCl

Back (Answer)

=O is replaced with 2 H’s. Occurs with both Aldehydes and Ketones.

#24

Front (Question)

EtSH

Back (Answer)

Replace =O with two -SEt. Occurs with both Aldehydes and Ketones.