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2.1.3 Amount of substances

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

the mole is…

Back (Answer)

the amount of substance in grams that has the same number of particles as there are atoms in 12g of carbon 12

#2
Front (Question)

relative atomic mass is…

Back (Answer)

the average mass of an atom compared to the mass of one atom of carbon 12

#3
Front (Question)

relative molecular mass is …

Back (Answer)

the average mass of a molecule compared to one twelfth of the mass of one atom of carbon 12

#4
Front (Question)

molar mass is…

Back (Answer)

the mass in grams of one mole of substance (gmol-1)

#5
Front (Question)

avogadro’s constant

Back (Answer)

the number of particles in one mole

#6
Front (Question)

mass =

Back (Answer)

n x Mr

#7
Front (Question)

no of particles =

Back (Answer)

n x 6.02 x 10^23

#8
Front (Question)

volume in (dm^3)

Back (Answer)

n/C

#9
Front (Question)

moldm^-3 can be made into gdm^-3 by…

Back (Answer)

multiplying by the Mr

#10
Front (Question)

avogadro’s number shows …

Back (Answer)

that there are 6.02 x 10^23 atoms in 12g of carbon 12

#11
Front (Question)

xH2O means …

Back (Answer)

water of crystallisation

#12
Front (Question)

salts that have water removed are …

Back (Answer)

anhydrous

#13
Front (Question)

empirical formula is…

Back (Answer)

the simplest whole number ratio of atoms in a compound

#14
Front (Question)

molecular formula is …

Back (Answer)

the actual number of atoms in a compound

#15
Front (Question)

how to work out the factor of an empirical formula

Back (Answer)

factor = mr of molecular formula / mr of empirical formula

#16
Front (Question)

to work out the molecular formula you …

Back (Answer)

empirical formula x factor

#17
Front (Question)

ideal gas equation

Back (Answer)

P(Pa)V = nRT

#18
Front (Question)

T=

Back (Answer)

273 +/- ?°C

#19
Front (Question)

R =

Back (Answer)

8.31

#20
Front (Question)

V (m^3) =

Back (Answer)

cm^3 / 10^6 or dm^3 / 1000

#21
Front (Question)

1 mole of any gas at room temp and room pressure =

Back (Answer)

25°C and 24dm^3

#22
Front (Question)

gas volume (dm^3) =

Back (Answer)

n x 24 (or 24,000 if answer is wanted in cm^3)

#23
Front (Question)

% yield =

Back (Answer)

actual yield / theoretical yield x 100

#24
Front (Question)

name two ways % yield can be lowered

Back (Answer)

• incomplete reactions • side reactions • losses during purification • transfer of substances