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moles and Avogadros constant.

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卡片总数: 8内容版本: v4公开卡包更新时间: 8/1/2026

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#1
正面 (问题)

What is the mole?

背面 (解答)

The amount of a substance that contains the same number of atoms or particles as 12g of carbon 12

#2
正面 (问题)

What is the value of the mole?

背面 (解答)

6.02x10^23 (avogadro’s constant)

#3
正面 (问题)

What is molar mass?

背面 (解答)

The mass of one mole of a substance

#4
正面 (问题)

What is an example of Mr?

背面 (解答)

Carbon = 12 Oxygen = 16 Nitrogen = 14

#5
正面 (问题)

What does the molar mass do?

背面 (解答)

It takes the same value as the atomic mass and helps calculate for Moles = mass/ molar mass

#6
正面 (问题)

What is the units of molar mass?

背面 (解答)

G/mol

#7
正面 (问题)

When 0.22g of pure barium is added to water, how many moles of Barium have been added?

背面 (解答)

Moles = mass/mr = 0.22/137.33 =16 x10^-4

#8
正面 (问题)

Modern pencils contain graphite rather than lead. In a pencil containing 0.642g of pure graphite, a form of carbon, calculate the amount in mol of graphite. Using Avogadro’s constant, calculate how many carbon atoms are present in this sample of graphite.

背面 (解答)

Moles=mass/mr =0.642/12 =0.0535 0.0535 x (6.02x10^23) =3.22x10^22