Back to marketplace

6.1.1 - Aromatic compounds

No description yet. This curated deck is ready for daily study.

Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (24)

#1
Front (Question)

Arenes

Back (Answer)

Aromatic molecules containing 1 or more benzene rings

#2
Front (Question)

-OH

Back (Answer)

Hydroxy -

#3
Front (Question)

NO2

Back (Answer)

Nitro -

#4
Front (Question)

F

Back (Answer)

Fluoro -

#5
Front (Question)

NH2

Back (Answer)

-amine

#6
Front (Question)

Benzoic acid

Back (Answer)

Benzene ring attached to COOH group Acid group is always highest priority (1’ priority)

#7
Front (Question)

Phenyl -

Back (Answer)

Prefix if attached to an akyl chain w/ more than 6 carbons OR w/ a carbon chain w/ a functional group

#8
Front (Question)

Kekule structure

Back (Answer)

Benzene is v. reactive Diff C-C bond lengths

#9
Front (Question)

Problems w/ Kekule’s structure

Back (Answer)

C-C bonds are all same lengths Benzene does not undergo addn. reactions readily (resistance to reaction) Enthalpy of hydrogenation 152kJ/mol less exothermic than expected

#10
Front (Question)

Delocalised electrons

Back (Answer)

Electrons shared between more than two atoms

#11
Front (Question)

Which model of benzene do we use now

Back (Answer)

Delocalised model

#12
Front (Question)

Using a labelled diagram. disprove Kekule

Back (Answer)

p-orbitals overlap sideways —> Delocalised pi-system above and below Planar carbon ring All bonds 120 degrees

#13
Front (Question)

Why do electrophiles react more easily w cyclohexane than w/ benzene

Back (Answer)

In benzene, pi-electrons are delocalised In cyclohexane, the pi-electrons are localised So benzene has a lower electron density And so benzene polarises the electrophile less

#14
Front (Question)

Priorities

Back (Answer)

COOH>…> hydrocarbons > F,Cl,Br,I> NO2

#15
Front (Question)

How did the scientist disprove Kekule

Back (Answer)

Using diffraction to find the carbon-carbon lengths

#16
Front (Question)

Why does phenol react more readily w/ electrophiles then benzene does

Back (Answer)

Lone pair from -OH group in phenol is drawn into the delocalised benzene ring so electron density increases and the electrophile is more strongly attracted

#17
Front (Question)

Electron donating groups

Back (Answer)

-OH -NH2 -CH3 2 (6),4 directing

#18
Front (Question)

Electron withdrawing groups

Back (Answer)

-NO2 -COOH 3’, (5) directing Less reactive so only one substitution

#19
Front (Question)

Why is bromine not attracted to benzoic acid

Back (Answer)

-COOH is an electron withdrawing group therefore pi-system becomes less dense and will not attract electrophiles as strongly

#20
Front (Question)

Electrophilic substitution w/ bromine and phenols

Back (Answer)

White ppt Decolourises bromine water

#21
Front (Question)

Nitration of benzene (nitrobenzene)

Back (Answer)

HNO3 H2SO4 (Conc. catalyst) 50 degrees HNO3 + H2SO4 —> NO2^+ + HSO4 ^- + H2O H+ + HSO4^- –> H2SO4

#22
Front (Question)

Dinitrobenzene

Back (Answer)

2 HNO3 Conc. H2SO4 70 degrees

#23
Front (Question)

Bromination of benzene

Back (Answer)

Occurs at RTP (electrophilic subsitution) in the presence of a halogen carrier Overall: C6H6 + Br2 –> C6H5Br + HBr Br2 + FeBr3 —> FeBr4^- + Br^+ H^+ + FeBr4^- —> FeBr3 + HBr

#24
Front (Question)

General formula for electrophilic substitution w/ benzene

Back (Answer)

AX + C6H6 —> C6H5A + HX A - Electrophile X - halogen