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Acids & Bases: QP
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Total cards: 2•Content version: v4•Public deck•Updated: 8/1/2026
Card preview (2)
#1
Front (Question)
Give an expression for Ka for propanoic acid (CH3CH2COOH). Use this expression to show that pH = pKa when half of the propanoic acid has reacted with sodium hydroxide. Ka = [3]
Back (Answer)
[1] ([H+] [CH3CH2COO-]) / [CH3CH2COOH] [2] [CH3CH2COOH] = [CH3CH2COO- ] [3] Ka = [H+]
#2
Front (Question)
Methyl orange and universal indicator are not suitable indicators for the titration of solutions of propanoic acid with sodium hydroxide. State the reason why each indicator is not suitable. [2]
Back (Answer)
[1] Methyl orange - would not change colour at the equivalence point [2] Universal indicator - idea of range of colours during titration/no distinct colour change