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The Final Chapter.

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Total cards: 7•Content version: v3•Public deck•Updated: 8/1/2026

Card preview (7)

#1
Front (Question)

Are conjugated or isolated bonds stronger and why?

Back (Answer)

Conjugated bonds- b/c they have resonance stabilization.

#2
Front (Question)

Is a cumulated diene or an terminal alkyne stronger?

Back (Answer)

terminal alkyne - the cumulated diene has a lot of reactive pi bonding in once place.

#3
Front (Question)

What is the expected product in a reaction of a conjugated diene and HBr.

Back (Answer)

two products - 1,2 bromoalkene, and 1,4 bromoalkene.

#4
Front (Question)

Under normal conditions (40C) for addition to conjugated dienes, what is the predominant product?

Back (Answer)

the 1,4 - addition, internal alkene is more stable.

#5
Front (Question)

Under cold conditions (-80C) for addition to conjugated dienes, what is the predominant product?

Back (Answer)

the 1,2 - addition, b/c the internal carbocation is more stable (forms easier.)

#6
Front (Question)

In which reaction is NBS used as a source of Br2?

Back (Answer)

Free-radical allylic bromination. (reacts with HBr by-product to regenerate molecule of Br2.)

#7
Front (Question)

Tell me about the REAL reason why 1,3 - butadiene is more stable than a similar compound with isolated double bonds.

Back (Answer)

1,3 - butadiene has four pi-bonding electrons that reside in two energy conformations. The lowest energy conformation contains 2 of these electrons, and evenly disperses them within the pi-orbitals of all four sp2 - hybridized carbons. The second pair of electrons reside in a slightly higher energy conformation, which allows them to only hangout between C1-C2 and C3-C4. This is why these carbons have more pi-bonding character. The partial pi-bonding character about the C3-C4 bond lowers the energy of the planar conformation, making it a more stable molecule.