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Aldehydes, Ketones and Carboxylic Acids

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Total cards: 24•Content version: v3•Public deck•Updated: 8/1/2026

Card preview (24)

#1
Front (Question)

malonic acid

Back (Answer)

cooh-ch2-cooh

#2
Front (Question)

succinic acid

Back (Answer)

cooh-ch2-ch2-cooh

#3
Front (Question)

glutaric acid

Back (Answer)

cooh-(ch2)3-cooh

#4
Front (Question)

adipic acid

Back (Answer)

cooh-(ch2)4-cooh

#5
Front (Question)

cinnamaldehyde

Back (Answer)

3-phenylprop-2-enal

#6
Front (Question)

Acrolein

Back (Answer)

prop-2-enal

#7
Front (Question)

phthalic acid

Back (Answer)

benzene-1,2-dicarboxylic acid

#8
Front (Question)

isophthalic acid

Back (Answer)

benzene-1,3-dicarboxylic acid

#9
Front (Question)

terephthalic acid

Back (Answer)

benzene-1,4-dicarboxylic acid

#10
Front (Question)

1* alc will give

Back (Answer)

aldehyde

#11
Front (Question)

2* alc will give

Back (Answer)

ketones

#12
Front (Question)

CH≡CH to CH2=CH3-CHO

Back (Answer)

H2O with Hg2+,H+(333K)

#13
Front (Question)

what happens if S is not used as poison for rosenmund reaction?

Back (Answer)

RCHO will undergoe reduction again & form 1* alc

#14
Front (Question)

compounds having CH=NH is called

Back (Answer)

imines

#15
Front (Question)

CH2-CH2-CN to CH3CH2CHO

Back (Answer)

SnCl2 + H2O + 2HCl

#16
Front (Question)

What is DIBAL-H

Back (Answer)

Diisobutylaluminium hydride

#17
Front (Question)

Benefit of DIBAL H

Back (Answer)

If a double bond is present in the compound along with triple bond, the double bond won’t get reduced.

#18
Front (Question)

Mild oxidising agents eg

Back (Answer)

CrO2Cl2/aci. KMnO4/alk. KMnO4/ aci. K2Cr2O7

#19
Front (Question)

benzene to benzophenone

Back (Answer)

C6H5-COCl (anhy. AlCl3)

#20
Front (Question)

why is aldehyde more reactive than ketone?

Back (Answer)

Since e’ releases from the alkyl group reduces carbon’s electrophilicity and steric reasons due to which nucleophile cannot easily attack carbon due to the presence of alkyl groups.

#21
Front (Question)

Why is OH needed to separate HCN into ions?

Back (Answer)

Since ions cannot be formed easily

#22
Front (Question)

CH3CHO to CH3CH(OH)CN

Back (Answer)

CN

#23
Front (Question)

Acetaldehyde cyanohydrin

Back (Answer)

2hydroxypropan nitrile

#24
Front (Question)

Why is NaHSO3 used with C=O and CHO?

Back (Answer)

It is used for separation & purification of CHO and CO from non-carbonyl compds