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Topic 12 Acid-Base Equilibria

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

Define an acid.

Back (Answer)

Proton donor.

#2
Front (Question)

Define a base.

Back (Answer)

Proton acceptor.

#3
Front (Question)

Conjugate acid-base pair

Back (Answer)

A base and its conjugate acid or an acid and its conjugate base.

#4
Front (Question)

Conjugate acid

Back (Answer)

When a base accepts a proton, the species formed is its conjugate acid.

#5
Front (Question)

Conjugate base.

Back (Answer)

When an acid donates a proton, the species formed is the conjugate base of the acid.

#6
Front (Question)

Amphoteric

Back (Answer)

A substance that can act as both an acid and a base.

#7
Front (Question)

What substances tend to be bases?

Back (Answer)

They must have a lone pair to accept a proton by forming a dative covalent bond with it. This means a base must contain an atom of the RHS of the periodic table, often oxygen.

#8
Front (Question)

What substances tend to be acids?

Back (Answer)

A substance containing a slightly positively-charged hydrogen, e.g., when it is bonded to a highly electronegative atom such as oxygen of a halogen.

#9
Front (Question)

Amphiprotic

Back (Answer)

A substance that can both donate and accept protons such as amino acids or HSO4^-. All amphiprotic substances are also amphoteric, but no the other way around.

#10
Front (Question)

Monoprotic acids

Back (Answer)

E.g., HCl, can donate one proton. (Also termed monobasic acids.)

#11
Front (Question)

Diprotic acids

Back (Answer)

E.g.,H2SO4, can donate 2 protons (also termed dibasic acids).

#12
Front (Question)

Diprotic base

Back (Answer)

E.g., a base that can accept 2 protons e.g., CO3^2-+ 2H+ –> H2CO3. Also termed diacidic bases.

#13
Front (Question)

Nitric acid as a base in the nitration of benzene.

Back (Answer)

Concentrated H2SO4 + concentrated HNO3 react: H2SO4 + HNO3<–> HSO4^- + H2NO3^+ H2SO4 is an acid; its conjugate base is HSO4-. HNO3 is a base; its conjugate acid is H2NO3^+.

#14
Front (Question)

When ammonia dissolves in water, this is an example of a conjugate acid-base pair.

Back (Answer)

NH3 (aq) + H2O (l) <–> NH4^+ (aq) + OH^- (aq) In the forward reaction: NH3 acts as a base & H2O acts as an acid. In the backward reaction: NH4^+ acts as an acid & OH- acts as a base.

#15
Front (Question)

Strong acid

Back (Answer)

Completely dissociates/ionises in aqueous solution. HCl(aq) –> H+(aq) + Cl-(aq)

#16
Front (Question)

Weak acid

Back (Answer)

Only partially dissocisates in aqueous solution, typically organic acids. CH3COOH(aq) <–> CH3COO-(aq) + H+(aq)

#17
Front (Question)

pH of an aqueous solution

Back (Answer)

The reciprocal of the logarithm to the base 10 of the hydrogen ion concentration measured in mol dm^-3. pH= -log[H+]

#18
Front (Question)

For strong acids, the [acid] is directly related to the [H+].

Back (Answer)

A solution of HCl of 0.100 mol dm^-3 produces a [H+] of 0.100 mol dm^-3.

#19
Front (Question)

How can you determine [H+] from pH?

Back (Answer)

[H+] = 10^-pH

#20
Front (Question)

Ka

Back (Answer)

Ka = [H+][A-]/[HA]

#21
Front (Question)

[A-]=[H+] at equilibrium. How?

Back (Answer)

Every time a molecule of HA dissociates, a H+ ion & A- ion are formed.

#22
Front (Question)

How can we find the pH of a weak acid?

Back (Answer)

Ka= [H+]^2/[HA], assuming the concentration of undissociated acid at equilibrium is equal to the concentration of acid initially as Ka is very small.

#23
Front (Question)

pKa

Back (Answer)

-log Ka

#24
Front (Question)

The larger the value of Ka…

Back (Answer)

… the stronger the acid.