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lecture 7

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卡片总数: 6内容版本: v4公开卡包更新时间: 8/1/2026

卡片预览 (6 张)

#1
正面 (问题)

If dihybrid cross doesn’t result in 1:1:1:1 ratio what can be inferred? define notations for: known and unknown linkage; known indep assort

背面 (解答)

• if genes are linked, the parental combination of gametes are overrepresetned • genese close together on the same chr are linked • known linked / • unknown linked . • indep assort ;

#2
正面 (问题)

Explaing crossing over

背面 (解答)

• the physical exchange of DNA b/w non-sister chromatids of homologs in prophase 1 • rare occurance • expect that most meiosis to have parental combination of gametes • c/o gives recombinant gametes • freq recomb gametes are proportional to the genetic distance b/w 2 genes

#3
正面 (问题)

Explain the first proposed model: Holliday Model

背面 (解答)

• nicking; occuring at the exact same spot on both homologs = dsDNA break • invasion; nicked strand invades the other nicked homolog; must have seq similar to continue • resolution; covalent linkage to form Holliday Junction

#4
正面 (问题)

How do you know if genes are linked? what are the expected ratios for a test cross and a dihybrid

背面 (解答)

• over-representation of parental phenotypes in F2 of test cross • progeny doesnt look like 1:1:1:1 • parental alleles were more likely to be inherited tgt than expected from independent assortment • dihybrid cross not expecting 9:3:3:1

#5
正面 (问题)

How do you measure genetic distance? define RF value

背面 (解答)

• NOT = to physical distance • recombinantion frequence proportional to the distance b/w linked genes • the further apart 2 loci are, the higher likelihood of a C/O occuring • if 2 loci are too far apart (>50 cM or mu) then they are unlinked but syntenic = located on the same chr • appear to assort independently

#6
正面 (问题)

How do you calculate RF value and what does >50%

背面 (解答)

(# of recombinants/total) x100% %RF = map units - either genes are broken in linkage by a centromere (unlinked bu syntenic) - or high mu probability of a c/o is so high its as if they sort independently