Back to marketplace

Aromatic Compounds

No description yet. This curated deck is ready for daily study.

Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (24)

#1
Front (Question)

What is the formula of benzene?

Back (Answer)

C6H6

#2
Front (Question)

Describe and explain the structure of a benzene molecule.

Back (Answer)

6x sigma bonds and a continuous ring shaped pi-bonding system above and below the plane of the ring. This is formed due to the overlap of the p-orbitals of each of the six carbon atoms.

#3
Front (Question)

Why is benzene considered to be stable?

Back (Answer)

The electrons in the pi-bond are delocalised across the six carbon atoms, thus the -ve charge is stabilised.

#4
Front (Question)

What evidence is there for benzene’s structure?

Back (Answer)

X-ray crystallography: all bond-lengths are the same (intermediate between C-c and C=C) Bromine water: NOT decolourised by benzene so must have insufficient e- density Enthalpy of hydrogenation: NOT -360kJmol-1 as Kekule’s model would have implied, but -208kJmol-1 where the difference in energy is the delocalisation energy. This quantifies the extra stability of benzene

#5
Front (Question)

What is the systematic name for the Kekule model?

Back (Answer)

Cyclohexa-1,3,5-triene

#6
Front (Question)

Describe the naming conventions for benzene.

Back (Answer)

Shorter groups are given as prefixes to benzene. Where the group has chain length >=7 or it includes a functional group, we instead use the phenyl- prefix.

#7
Front (Question)

What type of reaction does benzene undergo typically?

Back (Answer)

Electrophilic Substitution

#8
Front (Question)

Why does benzene undergo substitution rather than addition?

Back (Answer)

The delocalised pi bonding system has insufficient e- density to induce a dipole in an attacking molecule. Such a reaction would also disrupt the stable pi-bonding system.

#9
Front (Question)

Describe a typical Electrophilic substitution.

Back (Answer)

• Formation of Electrophile E+ • Electrophile gains 2x electrons from pi-bond to form dative bond to carbon • Existing hydrogen atom donates 2x electrons to re-complete pi bond, releasing H+ which bonds with -ve ion formed originally

#10
Front (Question)

How many electrons in contained within the intermediate of the Electrophilic substitution of benzene?

Back (Answer)

4x pi-electrons

#11
Front (Question)

How do we form the Electrophile for the nitration of benzene?

Back (Answer)

Formed in situ by reacting conc. H2SO4 and HNO3, to form NO2+. This is formed in situ due to its’ instability

#12
Front (Question)

What are the conditions + reagents for the nitration of benzene?

Back (Answer)

Reagents: HNO3 Conditions: H2SO4 catalyst (reformed due to reaction of H+, HSO4- at end) and 50 degrees Celsius

#13
Front (Question)

Why must we use a temperature of 50 degrees Celsius when nitrating benzene?

Back (Answer)

This temperature ensures the mono=-substitution of NO2+

#14
Front (Question)

How can we halogenate benzene molecules?

Back (Answer)

Since Benzene itself doesn’t have sufficient e- density to induce an electrophile from Br2/Cl2, we use AlBr3/AlCl3/etc to form a +ve species. This mono-substitutes.

#15
Front (Question)

Describe Friedel-Krafts acylation and alkylation.

Back (Answer)

Alkylation: CH3Cl + ALCl3 catalyst to add CH3 group Acylation: ClCOCH3 + AlCl3 catalyst to add COCH3 group

#16
Front (Question)

Why do benzene and Alkenes react differently?

Back (Answer)

Alkenes have higher electorn density in their pi-bonding system since the electrons are localised over 2x carbons rather than being delocalised over six. They can more readily induce a dipole in an incoming a molecule.

#17
Front (Question)

What reactant and conditions are used to reduce nitrobenzene into phenylamine?

Back (Answer)

[H+ such as NaBH4] + Sn/HCl (conc)

#18
Front (Question)

What typically defines a group as 2/4 directing?

Back (Answer)

Presence of lone pairs. This makes the group in question electron-donating, so it activates the pi bonding system and directs attacking Electrophile to 2/4 positions.

#19
Front (Question)

What typically defines a group as 3-directing?

Back (Answer)

Presence of double or triple bonds. These group are typically electron withdrawing so deactivate the benzene ring. This directs electrophiles to the 3 position.

#20
Front (Question)

What is a phenol?

Back (Answer)

An organic compound containing a benzene ring, with a hydroxyl group directly attached to it.

#21
Front (Question)

Why are phenols more reactive than aromatic alcohols and benzenes alike?

Back (Answer)

The -OH group donates a pair of electrons to the pi-bonding system, increasing e- density and making the molecule more susceptible to Electrophilic attack.

#22
Front (Question)

What are some typical comparisons we make between the reactions of phenols and benzene?

Back (Answer)

• Lower temperatures • Less concentrated reactants • No need for a catalyst/carrier/etc

#23
Front (Question)

How does phenol’s increased e- density increase reactivity?

Back (Answer)

Incoming molecules are polarised more strongly.

#24
Front (Question)

Describe the reaction between phenol and bromine water.

Back (Answer)

3x bromine atoms bond onto phenol in the 2, 4, and 6 positions. This can happen because of the increased e- density and the strong 2,4,6 directing effect of the -OH group promoting multiple substitution.