Back to marketplace

P1-3; Motion, Work, Energy and Power

No description yet. This curated deck is ready for daily study.

Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (24)

#1
Front (Question)

What is the difference between Accuracy and Precision?

Back (Answer)

Accuracy: close to true value Precise: repeatable results, close to each other

#2
Front (Question)

How do you read volumes in a test tube appropriately?

Back (Answer)

Take readings at eye level, and always take the reading from the bottom of the curve on the liquid’s surface.

#3
Front (Question)

Speed Equation?

Back (Answer)

Speed = Distance/Time

#4
Front (Question)

Conversion; Seconds - Minutes - Hours

Back (Answer)

Seconds /60 = Minutes/60 = hours

#5
Front (Question)

What is this time, in seconds? 1m 13s 48

Back (Answer)

73.48s 1 x 60 = 60 60 + 13.48 = 73.48s

#6
Front (Question)

If you run at 50m/s for 20s, how far have you ran?

Back (Answer)

V = dt d = v x t 50 x 20 = 1000m

#7
Front (Question)

Distance / Time Graphs; How do they show changes in speed.

Back (Answer)

The distance traveled over time = Speed, so if there is no change in distance, the object is stationary. It is moving at the same speed constantly, there will be a steady and constant change in distance. If the object is accelerating, a curve will form.

#8
Front (Question)

Units of Acceleration/Acceleration Equation

Back (Answer)

Acceleration = Change in velocity over time a = (delta)v \ t

#9
Front (Question)

Standard Units of Distance, Time, Speed and Acceleration

Back (Answer)

Distance = Metres (m) Time = Seconds (s) Speed = Metres per Second (ms-1) Acceleration = Metres per Second, per Second (ms-2)

#10
Front (Question)

How do you work out acceleration(gradient) from a graph?

Back (Answer)

Rise/Run or y/x Find a point on the graph where the data meets both the x and y axis, and then divide y/x to get acceleration.

#11
Front (Question)

What is the difference between weight and mass?

Back (Answer)

Weight is the concept of the effect of a gravitational field on a mass. (W = m g)

#12
Front (Question)

Recognize ALL VARIETIES of the Density Equation

Back (Answer)

p (density in kg/m3) = m(kg) / V(m3) m(kg) = p (density in kg/m3) x V(m3) V(m3) = m(kg) / p (density in kg/m3)

#13
Front (Question)

Express 8.92m^3 in cubic centimeters.

Back (Answer)

Length : 100cm = 1m Area : 10,000cm^2 = 1m^2 Volume : 1,000,000cm^3 = 1m^3 8.92 x 1,000,000 = 8,920,000cm^3

#14
Front (Question)

Recite Archimedes’ principle:

Back (Answer)

The volume of a body fully immersed in liquid can be deduced by the amount of liquid displaced by the object.

#15
Front (Question)

What are vectors?

Back (Answer)

Vectors are forces with magnitude and direction. All forces are They are most commonly represented my arrows.

#16
Front (Question)

List contact and non-contact forces:

Back (Answer)

Non-Contact: Contact: Magnetic force Friction Gravitational force Air resistance Electrostatic force Tension

#17
Front (Question)

Recite Newtons 1st law:

Back (Answer)

If a body is at rest and the forces acting on it are balanced then the body will remain at rest. If a body is moving and the forces acting are balanced then the body will keep moving at constant speed in a straight line.

#18
Front (Question)

State Hooke’s law;

Back (Answer)

Hooke’s law states that force applied to a spring is directly proportional to the extension experienced by the spring, and that constant of proportionality is k, the spring constant, during elastic behaviour. F = k x

#19
Front (Question)

What is the “limit of proportionality” in a spring?

Back (Answer)

The limit of proportionality is where the spring reaches its full extension, and then breaks from overextension and is unusable.

#20
Front (Question)

Force on a spring equation

Back (Answer)

Force (N) = spring constant (N/m) x extension of spring (m)

#21
Front (Question)

Recal Newton’s Second Law:

Back (Answer)

Newton’s Second Law of Motion states that when an unbalanced force acts on an object: • the direction of the object’s acceleration is the same as the direction of the unbalanced force • the magnitude of the object’s acceleration varies in direct proportion with the size of the unbalanced force • the magnitude of the object’s acceleration varies inversely with the mass of the object.

#22
Front (Question)

Recall: Newton’s 2nd law; Equation

Back (Answer)

Newton’s Second Law of Motion can be written as the following relationship: F = ma where: F = unbalanced force m = mass a = acceleration Note that when you use this relationship, F always stands for unbalanced force.

#23
Front (Question)

Pressure Calculation

Back (Answer)

p = F / A Pressure (Pa) = Force (N) / Area (m^2)

#24
Front (Question)

Explain the relationship of pressure and surface area:

Back (Answer)

Surface area and pressure are related because the amount of pressure put on a surface depends on the amount of surface it’s spread over.