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M6-Nitrogen Compounds

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Total cards: 15•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (15)

#1
Front (Question)

Amine functional group

Back (Answer)

C-NH2

#2
Front (Question)

Nucleophile

Back (Answer)

Electron pair donor

#3
Front (Question)

What is a base

Back (Answer)

Electron acceptor

#4
Front (Question)

Why do amines act as a base

Back (Answer)

Have lone pair on nitrogen

#5
Front (Question)

Haloalkane to amine

Back (Answer)

By Nucleophilic substitution Uses excess NH3 Dissolved in ETHANOL and pressure

#6
Front (Question)

Why is ammonia used in excess when reacting

Back (Answer)

Amine produced is a nucleophile which competes with the NH3 Causes formation of secondary, tertiary and quaternary salts by further substitution

#7
Front (Question)

Reduction of a nitrile

Back (Answer)

H2 and nickel catalyst used Usually 2H2 if one nitrile group

#8
Front (Question)

Formation of nitro benzene

Back (Answer)

Concentrated H2SO4 and HNO3 used 50°-60° reflux, By Electrophilic addition Nitration reaction

#9
Front (Question)

Reduction of nitrobenzene

Back (Answer)

Sn catalyst and concentrated HCL Reflux Reduction Represent reducing agent as [H] Normally need 6[6] to give 2 H to Nitrogen and 4 H to form water with oxygens from nitrogen

#10
Front (Question)

Amide classification

Back (Answer)

Primary, secondary or tertiary

#11
Front (Question)

Naming amides

Back (Answer)

Carbon chain with C=O takes priority If something other than hydrogen attached to N, N-… Follow rules for example N,N-Dimethyl…

#12
Front (Question)

Production of primary amide

Back (Answer)

Acyl chloride with excess NH3(l) to prevent further substitution

#13
Front (Question)

Formation of secondary amide

Back (Answer)

Acyl chloride and amine Used excess amine to prevent further substitution

#14
Front (Question)

Hydrolysis of amide

Back (Answer)

HCl(aq) Split amide leaving C=O and rest of molecule Uses H2O and HCl Form an ammonium salt as protonation

#15
Front (Question)

Basic hydrolysis of amide

Back (Answer)

Amide + NaOH(aq) —> Carboxylate salt + ammonia/amine Form ammonia/amine Also form a carboxylate salt with Na+ from NaOH with COO-