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Ch.15 Haloalkanes

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Total cards: 14•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

As the alkyl chain length of a haloalkanes increases the boiling point

Back (Answer)

Increases Due to more electrons in the longer chain leading to stronger London forces Which require more energy to overcome

#2
Front (Question)

From Cl to Br to I the boiling point

Back (Answer)

Increases The halogen gets bigger meaning more electrons leading to stronger London forces Which require more energy to overcome

#3
Front (Question)

Why are haloalkanes only slightly soluble

Back (Answer)

Cannot form H bonds

#4
Front (Question)

In a carbon- halogen bond which acts as the elecrophile

Back (Answer)

Carbon, because halogen atoms are more electronegative it makes the C delta +

#5
Front (Question)

Conditions for the hydrolysis of haloalkanes

Back (Answer)

Heated under reflux (too slow at room temp) with aqueous sodium hydroxide

#6
Front (Question)

Nucleophilic substitution of haloalkanes

Back (Answer)

carbon atom is slightly + attracts species containing lone pairs - nucleophiles nucleophile is attracted to electron poor atoms and donates electron pair forming a covalent bond a nucleophile can replace a halogen

#7
Front (Question)

C-halogen bonds from strongest to weakest

Back (Answer)

C-F this is because F is same size as C therefore better overlap C-Cl C-Br C-I

#8
Front (Question)

Rates of hydrolysis of haloalkanes

Back (Answer)

Weaker the C-halogen bond is the faster it will break resulting in it being more reactive

#9
Front (Question)

measuring hydrolysis in haloalkanes

Back (Answer)

aqueous silver nitrate H2O acts as nucleophile use ethanol solvent allowing water and haloalkane to mix OH subs for halogen halide ion react with Ag+ ions forming a silver halide precipitate

#10
Front (Question)

hydrolysis

Back (Answer)

halogen replaced by OH in nucleophilic substitution OH- nucleophile lone pair is attracted to and donated to the partially + C C-halogen bond breaks through heterolytic fission forms and alcohol and halide ion

#11
Front (Question)

ozone creation

Back (Answer)

in ozone layer UV splits O2 into 2 O radicals a steady state is then reached O2 + O = O3 then O3 is broken down again the rate of formation is the same as the rate of breakdown human activity in the use of organohalogen has disrupted this equilibrium

#12
Front (Question)

how do CFC’s (chlorofluorocarbons) deplete the ozone layer

Back (Answer)

UV in the stratosphere provides enough energy for the carbon - halogen bonds to break by homolytic fission forming radicals this is called photodissociation

#13
Front (Question)

equations for photodissociation of the ozone layer

Back (Answer)

propagation 1. Cl. + O3 –> ClO2. + O2 2. ClO. + O –> Cl. + O2 O3 + O –> 2O2

#14
Front (Question)

other than CFC’s what else causes the depletion of the ozone layer

Back (Answer)

NO. radicals form naturally when lightning strikes and as a result of aircraft travel they act as a catalyst in the same way as the Cl. radicals do