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Oxidation & Reduction in terms of Electrons

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Total cards: 6•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (6)

#1
Front (Question)

What are the formulae for the ions: Hydroxide: ??? Sulphate: ??? Nitrate: ??? Carbonate: ??? Ammonium: ???

Back (Answer)

Hydroxide: OH⁻ Sulphate: SO₄ ²⁻ Nitrate: NO₃ ⁻ Carbonate: CO₃ ²⁻ Ammonium: NH₄ ⁺

#2
Front (Question)

1 - If a substance is oxidised, does it lose or gain electrons? 2 - If a substance is reduced, does it lose or gain electrons? 3 - If a substance is oxidised and reduced, what type of reaction does it become?

Back (Answer)

1 - If a substance is oxidised, it loses electrons 2 - If a substance is reduced, it gains electrons 3 - If a substance is oxidised and reduced, the reaction is a redox reaction.

#3
Front (Question)

Ionic Equations: Write the following equation as an ionic equation: iron + copper sulfate → iron(II) sulfate + copper Fe + CuSO₄ → FeSO₄ + Cu

Back (Answer)

Ionic Equations: Fe + Cu ²⁺ + SO₄ ²⁻ → Fe²⁺ + SO₄ ²⁻ + Cu

#4
Front (Question)

What are spectator ions?

Back (Answer)

Ions that are unchanged in an ionic reaction. For example: Fe + Cu ²⁺ + SO₄ ²⁻ → Fe²⁺ + SO₄ ²⁻ + Cu The Sulphate ions, SO₄ ²⁻, appear on both sides of the equation unchanged This means that they are spectator ions and do not participate in the chemistry of the reaction So, they can be removed from the equation Fe + Cu ²⁺ → Fe²⁺ + Cu

#5
Front (Question)

Ionic Equations: The spectator ions can be removed from ionic equations as they do not participate in the chemistry of a reaction Remove the spectator ion(s) from the following ionic equation: Fe + Cu ²⁺ + SO₄ ²⁻ → Fe²⁺ + SO₄ ²⁻ + Cu

Back (Answer)

Ionic Equations: Fe + Cu ²⁺ → Fe²⁺ + Cu

#6
Front (Question)

Half Equations: After removing spectator ions from an ionic equation it becomes balanced and can be further split into two half equations illustrating oxidation and reduction individually. Split the following ionic equation into two half equations illustrating oxidation and reduction individually: Fe + Cu ²⁺ → Fe²⁺ + Cu

Back (Answer)

Half Equations: Fe → Fe²⁺ + 2e⁻ Cu²⁺ + 2e⁻→ Cu The iron has lost electrons to become a positive ion, so has been oxidised The positive copper ion has gained electrons to become an atom, so have been reduced