Back to marketplace

Shapes & Structures 2

No description yet. This curated deck is ready for daily study.

Total cards: 22•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (22)

#1
Front (Question)

Name the 5 quantum numbers

Back (Answer)

• n, principal quantum number • l, angular momentum quantum number • ml, magnetic quantum number • s • ms

#2
Front (Question)

What does each quantum number represent? • n • l • ml • s • ms

Back (Answer)

n = shell/energy l = type of orbital (magnitude of angular momentum), s = 0 for s-orbitals ml = number of degenerate orbitals (component of the orbital angular momentum on a particular axis / orientation of angular momentum). For a d-orbital, l = 2 → ml = 2, 1, 0 -1, -2 → 5 degenerate orbitals s = magnitude of spin (intrinsic angular momentum), always = 1/2 ms = orientation of spin (intrinsic angular momentum), = -1/2 or 1/2

#3
Front (Question)

orbital energy equation

Back (Answer)

En = -RHZ2/n2

#4
Front (Question)

Give formulae for: • Total #nodes • # angular • # radial

Back (Answer)

• Total #nodes = n - 1 = #angular + #radial • # angular = l (so all s = 0, all p = 1, all d = 2) • # radial = n - l - 1 Radial nodes: first appearance of each orbital type has none, then go up by 1 with each shell.

#5
Front (Question)

When is it correct that energy of 4s energy of 3d?

Back (Answer)

Up to Ni

#6
Front (Question)

Name the symmetry labels and what each represents

Back (Answer)

• σ: rotational symmetry about the internuclear axis, without a change in phase • π: nodal plane (change in phase) in internuclear axis If there is a centre of inversion (2 points equidistant but opposite directions from centre are equivalent): • g: no change in sign on passing through centre of inversion • u: change in sign on passing through centre of inversion

#7
Front (Question)

Draw the MO diagram for O2, and sketch each MO and assign its symmetry.

Back (Answer)

Card back image
#8
Front (Question)

For the first-period homonuclear diatomics up to & including __, sp mixing is strong enough to make the sigma-g orbital higher-energy than the pi-u orbital.

Back (Answer)

N

#9
Front (Question)

describe the effect of sp mixing on the following MOs • (2s)σg • (2p)σg • (2s)σu* • (2p)σu*

Back (Answer)

• (2s)σg becomes more bonding (lowered) • (2s)σg becomes less bonding (raised) • (2p)σu* becomes less antibonding • (2s)σu* becomes more antibonding

#10
Front (Question)

To obtain linear geometry, which AOs contribute to the HAOs?

Back (Answer)

sp s, pz (IN axis)

#11
Front (Question)

To obtain trig planar geometry, which AOs contribute to the HAOs?

Back (Answer)

sp2 s, pz, py

#12
Front (Question)

To obtain tetrahedral geometry, which AOs contribute to the HAOs?

Back (Answer)

s, pz, py, px

#13
Front (Question)

To obtain bent geometry, which AOs contribute to the HAOs?

Back (Answer)

sp3 but not equal s, pz, py, px with greater p-character

#14
Front (Question)

To obtain octahedral geometry, which AOs contribute to the HAOs?

Back (Answer)

sp3d2 s, px, py, pz, dz^2, dx^2-y^2

#15
Front (Question)

To obtain square planar geometry, which AOs contribute to the HAOs?

Back (Answer)

sp2d: s, px, py, dx^2-y^2 or p2d2: px, py, dx^2-y^2, dz^2

#16
Front (Question)

To obtain trig bipyramidal geometry, which AOs contribute to the HAOs?

Back (Answer)

sp3d: d, px, py, pz, d?? spd3: s, p??,

#17
Front (Question)

Why is BH3 sp2 hybridised rather than sp3?

Back (Answer)

• Want to minimise energy of HOMO • Sp2 arrangement has: • 3 x occupied sigma • A vacant boron p-orbital (non-bonding) • 3 x vacant sigma* • So HOMO = sigma, made from sp2 HAOs • Sp3 arrangement has: • 3 x occupied sigma • a vacant sp3 HAO (non-bonding) • 3 x vacant sigma*. • So HOMO = sigma, made from sp3 HAOs • HOMO of sp3 arrangement has more p-character than that of sp2 arrangement, so is higher in energy, so is less favourable Another way of thinking about it: don’t want to waste s-character on an unoccupied orbital. Highest preference for using lowest-energy (s) orbitals when building HAOs

#18
Front (Question)

Using diagrams, describe the conjugated system and bonding in the allyl cation, H2C=CH-C+H2, and draw the resonance structures.

Back (Answer)

Higher-energy MOs have more nodes, so shape of π MOs can be predicted with sine waves: • Begin sine wave one bond-length away from end of molecule • n AOs → n MOs, and first MO has no nodes, so highest-energy MO has (n - 1) nodes • MOs are labelled in order of energy: 1π, 2π, etc • Atoms drawn in a straight line for simplicity, but might be a simplification • Nodes are where wave changes sign / crosses axis • Height of wave predicts shape of MO (contribution each AO makes to it) • NB: when combining p-orbitals of different elements, AOs are different energies → MOs aren’t symmetrical → e- density isn’t even (highest where AO energy was lowest)

Card back image
#19
Front (Question)

How would you compare the energies of orbitals of the same type?

Back (Answer)

Poorer size/energy match between constituent AOs → worse interaction → lower energy

#20
Front (Question)

HOMO-LUMO interactions cause net reduction in energy of the highest-energy electrons. The best interaction is between the orbitals closest in energy, which are?

Back (Answer)

Whichever HOMO is highest-energy, & the LUMO of the other reactant.

#21
Front (Question)

State the most favourable angle of approach for nucleophiles,

Back (Answer)

1070

#22
Front (Question)

use diagrams to show that 107o is the best angle of nucleophilic approach

Back (Answer)

Card back image