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3.1.2 Amount of substance

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

Avogadro’s Constant (Nₐ):

Back (Answer)

6.02 x 10²³

#2
Front (Question)

Moles [2]:

Back (Answer)

• The unit of amount of substance - One mole is equal to 6.02 x 10²³ particles

#3
Front (Question)

Number of moles =

Back (Answer)

molecular mass (Mᵣ)

#4
Front (Question)

Relative atomic mass(Aᵣ) [definition]:

Back (Answer)

The average mass of an atom compared with 1/12 the mass of an atom

#5
Front (Question)

Relative molecular mass(Mᵣ) [definition]:

Back (Answer)

The average mass of a molecule compared with 12g of a carbon 12 atom

#6
Front (Question)

What is the standard reference point in chemistry?

Back (Answer)

Carbon 12

#7
Front (Question)

Avogadro’s Constant [info]:

Back (Answer)

One mol of any substance contains 6.02 x 10²³identical atoms/molecules/ions of that substance

#8
Front (Question)

Moles and concentration: Number of moles =

Back (Answer)

Concentration x volume (dm³)

#9
Front (Question)

Number of particles =

Back (Answer)

Avogadro’s constant (Nₐ) x Number of moles

#10
Front (Question)

Molecular formula [definition]:

Back (Answer)

The number of atoms of each element in a molecule

#11
Front (Question)

Empirical formula [definition]:

Back (Answer)

The smallest whole-number ratio of atoms of each element in a compound

#12
Front (Question)

The ideal gas equation:

Back (Answer)

pV=nRT

#13
Front (Question)

ideal gas equation meanings [5]:

Back (Answer)

p= pressure in Pa V= volume in M³ n= mol R= the gas constant (8.31 J K⁻¹ mol⁻¹ t= temperature in K

#14
Front (Question)

°C —> K =

Back (Answer)

+273

#15
Front (Question)

Mole [definition]:

Back (Answer)

The amount of substance that contains the same number of particles as there are in 12g of carbon 12

#16
Front (Question)

Standard solution [definition]:

Back (Answer)

A solution of known concentration

#17
Front (Question)

How do you make a standard solution?

Back (Answer)

-They are made by dissolving an accurately weighed, mass of solid in a volume of solvent using a volumetric flask

#18
Front (Question)

Volumetric flask [description]:

Back (Answer)

It has a thin neck which is marked with a line so it can be filled accurately to its correct capacity

#19
Front (Question)

Concentration [definition]:

Back (Answer)

A measure of how much solute is dissolved per unit solvent

#20
Front (Question)

Concentration [equation]:

Back (Answer)

Concentration = amount of solute (mol) (mol/dm³) ———————————— . volume of solvent (dm³)

#21
Front (Question)

Concentration [equation for cm³]:

Back (Answer)

Concentration = amount of solute x 1000 (mol) (mol/dm³) ———————————— . volume of solvent (cm³)

#22
Front (Question)

Percentage yield [definition]:

Back (Answer)

Percentage of how much product was actually made compared with the amount of product that was expected

#23
Front (Question)

Percentage yield [equation]:`

Back (Answer)

Percentage yield = Actual yield (%) —————————– x 100 . Theoretical yield

#24
Front (Question)

Atom economy [definiton]:

Back (Answer)

The percentage of the total mass of reactants that can be converted into desired product