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Topic 12.1 Strong and weak acids

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

Brønsted-Lowry Theory

Back (Answer)

Proposed the theory into how acids and bases react with each other (in 1923)

#2
Front (Question)

Conjugate acid-base pairs

Back (Answer)

Acid + conjugate base Base + conjugate acid (strong reactactant forms weak opposite product)

#3
Front (Question)

Monoprotic

Back (Answer)

Donates one proton (HCl is monoprotic/monobasic- as 1 mol of acid can neutralise 1 mol OH- ions)

#4
Front (Question)

Diprotic

Back (Answer)

Donates two protons (Sulfuric acid is diuretic/dibasic)

#5
Front (Question)

Anphoteric

Back (Answer)

A substance that can act as both an acid and a base (water is anphoteric)

#6
Front (Question)

Ammonia acid-base pairs

Back (Answer)

-Weak acid NH3 + H2O ⇌ NH4+ + OH- Base Acid Acid Base (NH3 and NH4 conjugate pair) (H2O and OH- conjugate pair)

#7
Front (Question)

Strong acids

Back (Answer)

Strong acids are almost completely dissociated in solution. –> Reverse reaction doesn’t take place so single direction arrow is used (HCl –> H+) –> pH increases by a factor of one for each 10x decrease of conc

#8
Front (Question)

Weak acids

Back (Answer)

Weak acids only partly dissociate <10% (a significant amount of undissociated acid is present). –> Represented using a reversible reaction arrow (HA ⇌ H+ + A-)–>(CH3COOH ⇌ CH3COO- + H+) –> pH increases 0.5 for each 10x decrease in concentration.

#9
Front (Question)

Equilibrium constant Ka

Back (Answer)

• Ka is the acid dissociation constant. • Used to quantify the degree to which an acid dissociates.

#10
Front (Question)

Calculating pH

Back (Answer)

pH is related to the hydrogen ion concentration (moldm^-3) of a solution. pH = -log[H+] (eg: pH = -log0.100 pH = 1)

#11
Front (Question)

Calculating [H+] from ph

Back (Answer)

[H+] = 10^-pH

#12
Front (Question)

Calculating pH of a weak acid

Back (Answer)

-Need to know the degree of dissociation of the acid -Use Ka the acid dissociation constant to show this ____________

#13
Front (Question)

pKa

Back (Answer)

pKa = -logKa -Larger Ka = stronger acid -Smaller Ka = weaker acid

#14
Front (Question)

Dissociation of water

Back (Answer)

Water ionises to form some H+ and OH- ions H2O ⇌ H+ + OH- Kc = [H+][OH-] / [H2O]

#15
Front (Question)

The ionic product of water, Kw

Back (Answer)

• Kw = [H+][OH-] • Kw is the ionic product of water. • It has a constant value at a given temperature (298K).

#16
Front (Question)

Strong base

Back (Answer)

• Sodium hydroxide is a strong base. • It is completely dissociated in water.

#17
Front (Question)

What is a buffer solution?

Back (Answer)

• They resist changes in pH • A buffer solutions pH is almost unchanged on the addition of small amounts of acid or base • A buffer solution can be made from a weak acid and a salt of the acid.

#18
Front (Question)

A buffer solution can be made by mixing:

Back (Answer)

• A weak acid with its conjugate base • A weak base with its conjugate acid

#19
Front (Question)

Calculating buffer pH

Back (Answer)

pH = pka + log [acid]/[base] (?) –> pH = (-logKa) + log [salt]/ [acid] [H+] = Ka x [acid]/[salt] pH = -log[H+]

#20
Front (Question)

Ka

Back (Answer)

Acid dissociation constant. HA(aq) ⇌ H+(aq) + A-(aq)

Card back image
#21
Front (Question)

pH of aqueous solutions of strong bases

Back (Answer)

When an acid is dissolved in water, it produces so many hydrogen ions that the small contribution of the water is insignificant, unless the acid concentration is very small. However the fact that water ionises is the reason why even the most alkene solutions contain some hydrogen ions. Sodium hydroxide is a strong base, so in dilute aqueous solutions we can consider it ions to be completely dissociated.

#22
Front (Question)

acid

Back (Answer)

• Proton donor • Positive charge/becomes more negative • Higher pH- weaker the acid • carboxylic- weak acid • Others strong

#23
Front (Question)

base

Back (Answer)

• Proton acceptor • Lone pair/becomes more positive • Higher pH- stronger base • OH- strong base • NH3- weak base

#24
Front (Question)

equivalence point

Back (Answer)

The equivalence point is where the moles of acid and the moles of base would neutralize each other according to the chemical reaction. (when an acid and base have reacted together in the exact proportions as dictatef by the stoichiometric equation)