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Chapter 2: Amount of substance

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Total cards: 14•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

What is the Avogadro constant?

Back (Answer)

6.022 × 10^23 mol-1

#2
Front (Question)

What is a mole? And what is the equation of it?

Back (Answer)

The amount of substance that contains 6.022x10^23 particles. Mole(n) = Mass (g) / Mr

#3
Front (Question)

what is the Concentration formula?

Back (Answer)

Concentration (mold dm^-3) = Moles (n) / Volume (dm^3)

#4
Front (Question)

What is the Ideal Gas Equation?

Back (Answer)

pV = nRT Where p = Pressure in Pa, standard pressure = 100,000 Pa V = Volume in meters cubed n = Number of moles of gas R = The Ideal Gas Constant at 8.31 J/K/mol T = Temperature in K, standard temprature = 298K(25°C)

#5
Front (Question)

What does PV equal?

Back (Answer)

PV = nRT

#6
Front (Question)

What is the Empirical formula?

Back (Answer)

Number of moles = mass of element / mass of 1 mole of element

#7
Front (Question)

Find the empirical formula of clacium carbonate 10.1 g of a white solid contains: • 4.01 g of calcium, • 1.20g of carbon, • 4.80 g of oxygen Ar = Ca(40.1) C(12.0) O(16.0)

Back (Answer)

moles of calcium = 4.01 / 40.1 = 0.1 moles of carbon = 1.2 / 12 = 0.1 moles of oxygen = 4.8 / 16.0 = 0.3 therefore the ratio is calcium : carbon: oxygen: 1 : 1 : 3 = CaCO3

#8
Front (Question)

What is the molecular Formula?

Back (Answer)

The molecular formula is the number of atoms of each element in 1 molecule of a compound.

#9
Front (Question)

The Emprical formula of compound x is x also has an Mr of 58 C : H : O 3 : 6 : 1 Find the molecular formula.

Back (Answer)

The Mr of C : H : O = 58 Therefore the molecular formula is also C3H6O

#10
Front (Question)

What is the equation for moles

Back (Answer)

Mole = Mass/Mr

#11
Front (Question)

What is the equation for atom economy?

Back (Answer)

% atom economy = Mass of desired product total mass of reactants x100

#12
Front (Question)

Find the atom econmy of sodium chlorate in: 2NaOH + CL2 → NaCl + H2O + NaOCl Mr of Na = 23 Mr of Cl = 35.5 Mr of O = 16 Mr of H = 1

Back (Answer)

Moles = 2 : 1 → 1 : 1 : 1 Therefore the masses must = 80g : 71g → 58.5g : 18g : 74.5g % atom economy = 74.5/151 x 100 = 49.3%

#13
Front (Question)

What is the formula for percentage yield?

Back (Answer)

percentage yield = Number of moles of product max nubmber of moles of the product x100

#14
Front (Question)

Back (Answer)