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Topic 3: Periodicity

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

Effective nuclear charge (Z*/Z eff) is the … The equation is Z eff =

Back (Answer)

Nuclear charge felt by an electron in the atom Feel charge of nucleus but often shielded by other electrons Z (atomic number) - S (shielding constant)

#2
Front (Question)

Trend in Z eff across periodic table

Back (Answer)

Increase Electrons added to same shell at roughly same distance from nucleus Don’t shield each other perfectly

#3
Front (Question)

Order of orbitals in ability to shield (high to low)

Back (Answer)

s, p, d, f

#4
Front (Question)

Trend of Z eff down periodic table

Back (Answer)

Increase Increased number of protons Atomic orbitals less effective at shielding

#5
Front (Question)

atomic radius =

Back (Answer)

half the distance between the centres of neighbouring atoms in a solid or, for non-metals, in a homonuclear molecule (e.g. O2, P4, S8)

#6
Front (Question)

Reason for jump in atomic radius between halogen and noble gas

Back (Answer)

Large increase Noble gas only have Van Der Waals Inert and monatomic

#7
Front (Question)

Trend in atomic radii across the periodic table

Back (Answer)

Decrease as Z eff increases Outer electrons feeling more effect of nuclear charge due to Z eff, pulling in electrons tightly and decreasing atomic radii

#8
Front (Question)

Trend in atomic radii down a group

Back (Answer)

Increase This shows that the valence shell (n) which the outer electrons occupy is more important than Z eff here

#9
Front (Question)

Ionic radius

Back (Answer)

derived from the distance between the centres of adjacent ions in a crystal, as determined using X-ray diffraction studies.

#10
Front (Question)

Trend in ionic radius in period 2 and 3

Back (Answer)

2 halves (as you move from positively to negatively charged elements Decrease for increasing atomic number in each half (Li, Be, B) (C, N, O, F) Large increase from B to C e.g. For Li+ (Na+), Be2+ (Mg2+) & B3+ (Al3+) The nuclear charge increases; at the same time the positive charge carried by the element increases [from +1 to +3] Remaining electrons feel increasing Z eff + drawn closer to nucleus Ions decrease in size For C4- (Si4-), N3- (P3-), O2- (S2-), & F- (Cl-) The nuclear charge increases; at the same time the negative charge carried by the element decreases [from -4 to -1] The effect is that the electrons feel an increasing Z eff, and are drawn closer to the nucleus Ions decrease in size Same for period 3

#11
Front (Question)

Ionisation energy

Back (Answer)

the energy required to remove one mole of electrons from one mole of gaseous species in their ground (or standard) state

#12
Front (Question)

Trend in ionisation energy across a period

Back (Answer)

General increase Decrease Be (2s2) to B (2s2 2p1) and P (2s2 2p3) to S (2s2 2p4) (period 3 follows same pattern) B readily looses p electron, have to break into Be full 2s sub shell which requires more energy S has a paired electron in 2p sub shell, paired electrons repel each other so are one more easily, P has unpaired sp electrons

#13
Front (Question)

Trend in ionisation energy down periodic table Group … is the exception? … to … has the same ionisation energy as … … to … has an … ionisation energy as …

Back (Answer)

Decrease due to increasing quantum number n 13 Al to Ga: increase due to increased Z eff due to less effective shielding from 3d orbitals In to Tl: increase due to increased Z eff due to less effective shielding by 4f orbitals

#14
Front (Question)

Electronegativity Pauling’s values range from …

Back (Answer)

The power [ability] of anatom in a molecule to attract electrons to itself. 0 → 4

#15
Front (Question)

Trends in electronegativity

Back (Answer)

χ increases across a group due to increasing Z off χ decreases down a group due to increasing principle quantum number, n

#16
Front (Question)

Electron affinity Ea is … for exothermic Ea is … for endothermic

Back (Answer)

the energy released when 1 mole of electrons is added to 1 mole of gaseous atoms in their ground (or standard) state Positive Negative (Opposite to usual)

#17
Front (Question)

Electron gain enthalpy (ΔegHo)

Back (Answer)

the change in standard molar enthalpy when a gaseous atom gains an electron

#18
Front (Question)

Equation for relationship between electron affinity and electron gain enthalpy

Back (Answer)

ΔegHo = –Ea –(5/2)RT

#19
Front (Question)

Trends in electron affinity across a period

Back (Answer)

Increases due to increasing Z eff and decreasing atomic radii

#20
Front (Question)

Electron affinity for Be/Mg (from Li/Na)

Back (Answer)

Decrease Be 2s2 Mg 3s2 s sub shell full so added electron needs to occupy empty np shell

#21
Front (Question)

Electron affinity for noble gases (from halogens)

Back (Answer)

Decrease have a full shell so the added electron needs to enter the (n+1) shell

#22
Front (Question)

Electron affinity for N/P (from C/Si)

Back (Answer)

Decrease N: 2s2 2p3 configuration P: 3s2 3p3 configuration Adding electron must pair unpaired p electron which causes repulsion of electrons and reduces stability

#23
Front (Question)

Why does SiH4 react spontaneously in air to form SiO2 and water but CH4 is stable given thermodynamic data states they both should

Back (Answer)

Kinetics O from O2 would need to attack central C but C is well shielded Si is larger so has more room to attack so is sterically hindered Si has ability too expand its octet as its empty d-orbitals (3d) closer in energy to p-orbitals (3p) than for C as its 3d orbitals a lot higher in energy than 2p

#24
Front (Question)

Account for the trends in values of the atomic radii of the group 14 elements

Back (Answer)

General trend of increasing atomic radii as a group is descended is due to increasing values of n * C→ Si follows trend in increasing due the higher n. * Si→ Ge shows only a very slight increase as the Ge valence containing poorly shielding d-orbital. This increases Zeff to almost overcome the increasing n. * Ge→ Sn again shows return to trend with increasing n . * Sn → Pb shows strong reversal by increasing radii. This is due to Pb valence now containing poorly shielding f-orbitals and this is enough to allow Zeff to overcome increasing n