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Reagents Chapter 17

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (24)

#1
Front (Question)

KMnO4 + Aromatic Alkane

Back (Answer)

Carboxylic acid. Will replace the most acid H, or the group on the benzene ring.

#2
Front (Question)

KMnO4 + Aldehyde

Back (Answer)

Carboxylic acid anion. The KMnO4 will replace the H with O-. A later addition of an acid would protonate.

#3
Front (Question)

KMnO4 + Alcohol

Back (Answer)

Carboxylic acid. =O replaces the hydrogens of the Alcohol carbon.

#4
Front (Question)

Ag2O + Aldehyde

Back (Answer)

Carboxylic acid anion.

#5
Front (Question)

Ag(NH3)2+ + Aldehyde

Back (Answer)

Carboxylic acid anion.

#6
Front (Question)

CrO3 or H2CrO4 + Aldehyde

Back (Answer)

Carboxylic acid.

#7
Front (Question)

CrO3 or H2CrO4 + Alcohol

Back (Answer)

Carboxylic acid.

#8
Front (Question)

K2Cr2O7 + Alcohol

Back (Answer)

Carboxylic acid.

#9
Front (Question)

Alcohol + Carboxylic Acid

Back (Answer)

Ester. The H of the Alcohol combines with the OH of the Carboxylic acid and leaves as a H2O

#10
Front (Question)

Alcohol + Acid Chloride

Back (Answer)

Ester. The H of the Alcohol combines with the Cl of the Acid Chloride and leaves

#11
Front (Question)

Alcohol + Anhydride

Back (Answer)

Ester and/or Carboxylic Acid. Carboxylic on side that keeps its Oxygen, add OR to side that doesn’t.

#12
Front (Question)

Alcohol + Ester

Back (Answer)

Different Ester. Different Alcohol (?)

#13
Front (Question)

Alcohol + Amide

Back (Answer)

No reaction.

#14
Front (Question)

Amine (R2NH) + Carboxylic Acid

Back (Answer)

Amide.

#15
Front (Question)

Amine (R2NH) + Acid Chloride

Back (Answer)

Amide.

#16
Front (Question)

Amine (R2NH) + Anhydride

Back (Answer)

Amide + Carboxylic Anion. Splits at the Oxygen

#17
Front (Question)

Amine (R2NH) + Ester

Back (Answer)

Amide

#18
Front (Question)

RMgX or RLi + CO2

Back (Answer)

Carboxylic Acid

#19
Front (Question)

RMgX or RLi + Carboxylic Acid

Back (Answer)

Carboxylic Acid Anion and RH NO REACTION

#20
Front (Question)

RMgX or RLi + Acid Chloride

Back (Answer)

3* Alcohol

#21
Front (Question)

RMgX or RLi + Anhydride

Back (Answer)

3* Alcohol

#22
Front (Question)

RMgX or RLi + Ester

Back (Answer)

3* Alcohol. The OR of the Ester leaves and could be protonated

#23
Front (Question)

RMgX or RLi + Amide

Back (Answer)

RH and Amide Anion. (R will steal the H on the nitrogen)

#24
Front (Question)

LiAlH4 + Carboxylic Acid

Back (Answer)

1* Alcohol