5.2.3 redox and electrode potentials
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Reduction half equation
Br2 (aq) + 2e- > +2 Br - (aq) electrons on left electron acceptor, oxidising agent
Oxidation half equation
2I- (aq) > I2 (aq) + 2e- electrons on right electron donor, reducing agent
Thiosulfate redox titration
Redox titration between I2 and S2O3^2- Yellow/brown solution > colourless Starch indicator added near the end > from blue/black > colourless
Manganate redox titration
Redox titration between Fe2+ and MnO4 - Purple > colourless MnO4-(aq) + 8H+ (aq) + 5Fe2+ (aq) > Mn2+ (aq) + 4H2O (l) + 5Fe3+ (aq)
why does a voltage form
more negative electron has more of a tendency to oxidise and release electrons compared to less negative e.g. Zn > Zn2+ + 2e- more electrons build up on more negative electrode potential difference created between 2 electrodes negative strip is negative terminal and less positive is positive terminal
why use a high resistance voltmeter
stop the current from flowing in the circuit in this state, it is possible to measure the maximum possible potential difference (E) reactions will not be occurring as the very high resistance voltmeter stops the current from flowing
salt bridge
allows free moving ions to conduct the charge usually potassium nitrate wire not used as the metal wire would set up its own electrode system with the solutions
what happens if current is allowed to flow
reactions will then occur separately at each electrode voltage falls to zero as reactants are used up
measuring electrode potential of a cell
connect to another half-cell of known potential and PD between the 2 half-cells are measured can assign a relative potential to each electrode by linking it to a reference electrode (hydrogen electrode) which is given a potential of O V
standard electrode potential
potential difference measured when an electrode system is connected to the hydrogen electrode system, and standard conditions (1M, 100kPa, 298K) apply
more negative half cell
oxidises go backwards Zn (s) > Zn2+ (aq) + 2e-
less negative half cell
reduces go forwards Fe2+ (aq) + 2e- > Fe (s)
Ecell
= Ered - Eox more neg - less neg
effect of concentration on cell e.m.f
increasing concentration of reactants > increase in EMF > side with fewer moles
Effect of temperature on cell e.m.f
most Ecells are exothermic so increasing would decrease EMF if positive, reaction might occur however reaction will not occur or will occur so slowly that it effectively doesn’t happen if the reaction has a high activation energy, the reaction will not occur
uncatalysed reaction between 2 negative ions
repulsion between ions results in high activation energy making a very slow reaction
cells
electrochemical cells can be used as source of electrical energy are non-rechargeable when the reactions that occur within them are non-reversible
hydrogen fuel cell
2H2 + O2 > 2H2O maintain a constant voltage over time as they have a constant supply of O2 and H2 so maintain constant conc of reactants
adv of fuel cells
less pollution and less CO2 greater efficiency
limit of fuel cells
limited lifetime (regular replacement and disposal) and high production costs use of toxic chemicals in their production