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exam 1 pt 4

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Total cards: 12•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

Examination a Lineweaver Burk plot for an enzyme system after an inhibitor is added reveals a sudden [REDACTED]. Which of the following statements best describes what is happening at the enzyme level? increases Y, increases X, increases slope

Back (Answer)

increase y - noncompetitive increase x - competitive increase slope – uncompetitive

#2
Front (Question)

In ethanol sensitivity, there are two enzymes that clear the dangerous material. Why doesn’t the [REDACTED] clear the material even though the [REDACTED]? Could be asking: why doesn’t the cytoplasmic aldehyde dehydrogenase clear the dangerous material even though the acetaldehyde (the compound that causes the ethanol sensitivity) is present?

Back (Answer)

Cystoplasmic ALDH has a very high km, which makes it very inefficient if the concentration isn’t high. Because mitochondrial enzyme is less active, the cytoplasmic form functions, and it causes acetaldehyde to escape to the blood.

#3
Front (Question)

A technician is examining the amino acid sequence of a mutated enzyme cannot be inactivated by protein kinase A. The technician reports that an amino acid: [REDACTED], has been mutated to [REDACTED] and this prevents phosphorylation. Is this statement reasonable or has an error been made? 3

Back (Answer)

Kinase adds phosphoryl group to serine, threonine, tyrosine Can’t be phosphorylated with alanine If mutated to alanine or anything other than the three above, statement is reasonable

#4
Front (Question)

[REDACTED] have excellent potency and work very well to inhibit their target enzyme. What issue do these have that makes them challenging as a useful pharmacologic? transition + suicide

Back (Answer)

Transition State Enz – they are long-lasting, can be reused, and destroy other cells. Too unstable Suicide Enz – irreversible attaches itself to the enz through covalent bonding. Whole new enz is made. Unpredictable, toxic, and extremely difficult to dose properly.

#5
Front (Question)

Which of the following diseases tends to resolve positively over time?

Back (Answer)

hers disease

#6
Front (Question)

Considering a muscle cell [REDACTED]. What is the likely form and state of phosphorylase? (Choose form and state) stimulated by epinephrine but is overloaded with ATP. – High AMP – High ATP – High Glucose-6-Phosphase – Scarce Glucose-6-Phosphase –

Back (Answer)

stimulated by epinephrine but is overloaded with ATP. – A form R state. High AMP – B form R state High ATP – B form T state High Glucose-6-Phosphase – B form T state Scarce Glucose-6-Phosphase – B form R state

#7
Front (Question)

If phosphorylase [REDACTED] phosphorylated what is the likely state, form, and activity of phosphorylase? (Select state, form, activity) Phosphorylase B is phosphorylated

Back (Answer)

Phosphorylase B is phosphorylated – It becomes the Phosphorylase A in the R state, and it is active.

#8
Front (Question)

Why can liver cells generate glucose, but muscle cells cannot?

Back (Answer)

Because muscle cells lack glucose-6-phosphatase, they cannot convert glucose-6-phosphate to glucose. This is why they need to get glucose from the blood.

#9
Front (Question)

Both Hers disease and Type 1 Von Gierke disease possess the symptom of hypoglycemia. Why does Von Gierke also have the threat of lactic acidosis?

Back (Answer)

Because people with Von Gierke do not have glucose-6-phosphatase in their liver cells. This leads to the liver converting glucose-6-phosphate to lactic or pyruvate through glycolysis.

#10
Front (Question)

Considering a [REDACTED] cell stimulated by epinephrine [REDACTED] What is the likely form and state of phosphorylase? muscle cell, overloaded by ATP

Back (Answer)

The phosphorylase will be A in the R state REGARDLESS of what the second redacted says. EXCEPT if it says it’s overloaded by glucose, then A will be in the T state

#11
Front (Question)

In [REDACTED] disease, what is the enzymatic failure? Hers disease, von gierke disease

Back (Answer)

Hers Disease = Absence of Liver Phosphorylase Von Gierke disease = absence of Glucose-6-phosphatase

#12
Front (Question)

Determine if the provided statement is correct or incorrect. If the statement is incorrect, determine if clause (A) or (B) or both possesses an error. (A) Glucose is removed from glycogen by [REDACTED], (B) this is how we know [REDACTED]. A) phosphorylase ___ B) ATP usage ____ A) glucose-6-phosphate____ A) glucose-1-phosphate_____

Back (Answer)

A) phosphorylase TRUE B) ATP usage FALSE A) glucose-6-phosphate FALSE A) glucose-1-phosphate TRUE