Back to marketplace

Substitution Reactions of Alkanes

No description yet. This curated deck is ready for daily study.

Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (24)

#1
Front (Question)

why are alkanes considered to be fairly unreactive

Back (Answer)

• because they contain only carbon and hydrogen atoms - and only have single bonds

#2
Front (Question)

why do alkane’s single bonds make them unreactive

Back (Answer)

• they are not very polar • so they dont undergo reactions with substances that are reactive • such as acids, alkalis and reactive metals

#3
Front (Question)

what is a simple example of a substitution reaction between methane and chlorine gas

Back (Answer)

CH4 + Cl2 = CH3Cl + HCl

#4
Front (Question)

what is happening during the substitution reaction and what is it called

Back (Answer)

• one of the hydrogen atoms from methane have been replaced by a chlorine atom • in this case, it would be called chlorination

#5
Front (Question)

what is the broader name given to substitution reactions using halogens

Back (Answer)

halogenation

#6
Front (Question)

what does a mechanism do in chemistry

Back (Answer)

• it tries to explain the actual changes that happen during a reaction • especially with the bonding between the atoms

#7
Front (Question)

what is a mechanism in chemistry (definition)

Back (Answer)

• a sequence of two or more steps • each one represented by an equation • that shows how a reaction takes place

#8
Front (Question)

what happens when you mix chlorine with methane at room temperature

Back (Answer)

no reaction occurs

#9
Front (Question)

what are the two conditions that need to be met in order for a reaction to occur

Back (Answer)

• there needs to be a sufficient rise in temperature - or it needs to be exposed to ultraviolet radiation (sunlight)

#10
Front (Question)

what does the ultraviolet radiation affect

Back (Answer)

• the chlorine - not the alkane (methane)

#11
Front (Question)

what does the ultraviolet light do to the chlroine

Back (Answer)

• it breaks the chlorine molecule (Cl2) into chlorine atoms

#12
Front (Question)

how are the outer electrons of this broken chlorine molecule distributed

Back (Answer)

• the bond in a chlorine molecule consists of a shared pair of electrons • which are equally shared between the two atoms • so when broken, each chlorine atoms takes one electron from the shared pair

#13
Front (Question)

what is this kind of bond breaking between chlorine molecules, for example, called

Back (Answer)

homolytic fission

#14
Front (Question)

what equation shows the chlorine molecule being broken down into two chlorine atoms and what is this step called

Back (Answer)

• Cl2 = Cl. + Cl. (notice the dots) - this step is called initiation

#15
Front (Question)

what does the dot represent

Back (Answer)

an unpaired electron

#16
Front (Question)

if the dot represents and unpaired electron, what does that make and not make Cl.

Back (Answer)

• it doesnt make it an ion or a molecule - but instead it is called a free radical

#17
Front (Question)

what is a free radical

Back (Answer)

• a species with an unpaired electron • ‘species’ refers to any substance that can be represented by a formula • which includes atoms, molecules, ions and radicals

#18
Front (Question)

how would chlorine radicals and methane molecules interact and why

Back (Answer)

• when they collide the chlorine radical will remove a hydrogen atom from the methane molecule • this is because radicals are very reactive

#19
Front (Question)

what is the equation for this process and what is this step called

Back (Answer)

• Cl. + CH4 = CH3. + HCl - this called propagation (1)

#20
Front (Question)

what would the newly created molecular radical now react with, along with this formula

Back (Answer)

• it would react with chlorine molecules to produce chlorine radicals • CH3. + Cl2 = CH3Cl + Cl.

#21
Front (Question)

what is that step called

Back (Answer)

propagation (2)

#22
Front (Question)

why are the two steps called propagation

Back (Answer)

• because both equations involve one radical reacting with molecule • which produces one radical and one molecule

#23
Front (Question)

what is the overall product when the two propagation steps are combined

Back (Answer)

CH4 = CH3Cl

#24
Front (Question)

what is the last reaction that can take place

Back (Answer)

• two radicals colliding and reacting with each other - to form a stable molecule