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卡片总数: 24内容版本: v4公开卡包更新时间: 8/1/2026

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#1
正面 (问题)

what is the molecular formula of benzene?

背面 (解答)

C6H6

#2
正面 (问题)

what are the properties of benzene? mp, bp, solubility

背面 (解答)

physical properties: benzene is a colourless liquid at rtp. it is highly volatile and flammable, and is toxic and carcinogenic melting & boiling points: melting point ⮕ 5.5C boiling point ⮕ 80C. as benzene is a non-polar molecule, only a small amount of energy is needed to overcome the weak dispersion forces between molecules, so benzee has low melting & boiling points solubility: being a non-polar molecule, benzene is insoluble in polar solvents but soluble in non-polar solvents. benzene can also be used as a non-polar solvent

#3
正面 (问题)

LO: describe the structure of benzene

背面 (解答)

sp² hybridisation in benzene • each carbon is bonded to 2 other carbons and 1 hydrogen. (3 bond pairs) • each carbon atom is sp² hybridised, as the mixing of 1 s orbital and 2 p orbitals gives 3 sp² hybrid orbitals oriented at 120° to one another. one p orbital remains unhybridised, and is arranged perpendicular to the 3 sp² hybrid orbitals. • the geometry around each carbon atom in benzene is trigonal planar with C-C-C bond angle of 120° bonds in benzene • there are 6 C-C sigma (σ) bonds in benzene, each of which is formed from the head-on overlap of one sp² hybrid orbital of one carbon atom with one sp² hybrid orbital of the adjacent carbon atom. • there are also 6 C-H single bonds, each of which is an s-sp² σ bond formed from head-on overlap of the 1s atomic orbital of H and the sp² hybrid orbital of C. • the remaining unhybridised p orbitals of the 6 carbon atoms are all parallel to one another due to the planarity of the benzene molecule. all 6 unhybridised p orbitals overlap side-on with each other equally to produce 2 continuous rings of π electrons above and below the plane of the benzene ring, also known as the delocalised π electron cloud. • the 6 electrons found in this delocalised π electron cloud are free to move throughout the entire π electron cloud, so the electrons are delocalised.

#4
正面 (问题)

what are the 2 implications of the π electron cloud delocalisation?

背面 (解答)

• the delocalised π electron cloud causes all carbon-carbon bond lengths to be equal, creating a planar, regular hexagonal shape • the delocalised π electron cloud prevents benzene from undergoing any of the typical addition reactions that alkenes show for pt 1: all 6 carbon-carbon bonds of benzene are identical in length and intermediate between a C-C bond length and a C=C bond length. the carbon-carbon bond energy in benzene is also between that of a C-C bond and a C=C bond

#5
正面 (问题)

LO: why does the delocalised π electron cloud prevent benzene from undergoing any of the typical addition reactions that alkenes show? i.e. why is there a difference in reactivity between benzenes & alkenes?

背面 (解答)

• like electron-rich alkenes, the π electron cloud in benzene attracts electrophiles. however, the delocalisation of electrons in the π electron cloud in benzene results in extra stability of benzene. • as a result, the π electron cloud in benzene is less susceptible to attack by electrophiles compared to the C=C double bonds in alkenes. hence, benzene requires stronger electrophiles to react as compared to alkenes. • benzene undergoes electrophilic substitution instead of electrophilic addition, as electrophilic addition destroys the delocalised π electron cloud, which requires a significant amount of energy which is highly unfavourable. benzene preferentially undergoes electrophilic substitution reactions which preserves its aromaticity

#6
正面 (问题)

what are the reagents, conditions and observations for electrophilic substitution of benzene with chlorine (chlorination)?

背面 (解答)

reagents & conditions: - Cl2 (g), FeCl3 (s) as Lewis acid catalyst, warm OR - Cl2 (g), Fe (s), warm observations: - decolourisation of greenish-yellow Cl2 (g) AND - white fumes of HCl (g) Lewis acids accept electron pairs

#7
正面 (问题)

what are the reagents, conditions and observations for electrophilic substitution of benzene with bromine (bromination)?

背面 (解答)

reagents & conditions: - Br2 (l), FeBr3 (s) as Lewis acid catalyst, warm - Br2 (l), Fe (s), warm observations: - decolourisation of reddish-brown Br2 (l) AND - white fumes of HBr (g) Lewis acids accept electron pairs

#8
正面 (问题)

what are the reagents, conditons and observations for electrophilic substitution of benzene with concentrated nitric acid (nitration)?

背面 (解答)

reagent: - concentrated HNO3 conditions: - concentrated H2SO4 as Bronsted-Lowry acid catalyst - maintained at 55C observation: - pale yellow oily liquid formed Bronsted-Lowry acids donate protons

#9
正面 (问题)

what are the reagents, conditions and observations for electrophilic substitution of benzene with halogenoalkanes (Friedel-Crafts alkylation)?

背面 (解答)

reagent: - chloroalkane conditions: - AlCl3 as Lewis acid catalyst - warm observations: - white fumes of HCl (g) Lewis acids accept electrons

#10
正面 (问题)

what are the reagents, conditions and observations for electrophilic substitution of methylbenzene with chlorine?

背面 (解答)

reagents & conditions: - Cl2 (g), FeCl3 (s), room temperature, absence of UV observations: - decolourisation of greenish-yellow Cl2 (g) AND - white fumes of HCl (g) FeCl3 (s) acts as a Lewis acid catalyst room temp & absence of UV prevents free radical sub on alkyl side chain

#11
正面 (问题)

what are the reagents, conditions and observations for electrophilic substitution of methylbenzene with bromine?

背面 (解答)

reagents & conditions: - Br2 (l), FeBr3 (s), room temperature, absence of UV observations: - decolourisation of reddish-brown Br2 (l) AND - white fumes of HBr (g) FeBr3 (s) acts as a Lewis acid catalyst room temp & absence of UV prevents free radical sub on alkyl side chain

#12
正面 (问题)

what are the reagents, conditions and observations for electrophilic subsitution of methylbenzene with concentrated nitric acid?

背面 (解答)

reagent: - concentrated HNO3 conditions: - concentrated H2SO4 as Bronsted-Lowry acid catalyst - maintained at 30C observation: - yellow oily liquid formed Bronsted-Lowry acids donate protons

#13
正面 (问题)

what are the reagents, conditions and observations for electrophilic substitution of methylbenzene with halogenoalkanes? (friedel-crafts alkylation)

背面 (解答)

reagent: - chloroalkane conditions: - AlCl3 (s) as Lewis acid catalyst - room temperature observation: - white fumes of HCl (g) Lewis acids accept electrons

#14
正面 (问题)

what are the 2 ways substituents on a benzene ring affect the reactivity of the benzene ring towards electrophilic substitution?

背面 (解答)

• inductive effect • delocalisation electron-donating groups increase the electron density in the benzene ring, while electron-withdrawing groups decrease the electron density in the benzene ring.

#15
正面 (问题)

how does the inductive effect arise?

背面 (解答)

inductive effect arises from the polarisation of electron density in a bond due to the electronegativity of nearby atoms. electron-withdrawing groups via inductive effect: - electron-withdrawing groups like -OH, -NH2, -Cl, inductively withdraw electron density from the benzene ring via the σ bond as O, N and halogens are more electronegative than the C atom in the benzene ring. electron-donating groups via inductive effect: - electron-donating alkyl groups like -CH3, CH2CH3, inductively donate electron density into the benzene ring via the σ bond.

#16
正面 (问题)

how does delocalisation arise?

背面 (解答)

delocalisation occurs when p orbitals on 3 or more adjacent orbitals overlap, forming a π electron cloud. for substituents with a p orbital on the atom joined to the benzene ring, the p orbital can overlap with the π electron cloud of the ring. electron-donating groups via delocalisation - electron-donating groups like -OH, -NH2, -Cl, have a lone pair of electrons in the p orbital of th atom directly joined to the benzene ring, and can thus donate the lone pair of electrons into the benzene ring via delocalisation electron-withdrawing groups via delocalisation - in electron-withdrawing groups like -CHO, COOH, NO2, the atom directly joined to the benzene ring forms double/triple bonds to electronegative atoms like O or N, thus electron density in the benzene ring is drawn away by these electronegative atoms via delocalisation

#17
正面 (问题)

how does delocalisation and inductive effect affect the reactivity of the benzene ring?

背面 (解答)

• inductive effect and delocalisation do not necessarily act in the same direction. when 2 effects are opposing, the stronger effect dominates • eg the -OH group is electron-withdrawing via inductive effect but electron-donating via delocalisation. • substituents that are overall-electron-donating towards the benzene ring will increase the electron density of the benzene ring, making it more reactive towards electrophilic attack. they are called activating groups. eg -OH, -NH2, alkyl groups • substituents that are overall electron-withdrawing from the benzene ring will decrease the electron density of the benzene ring, making it less reactive towards electrophilic attack. they are called deactivating groups. eg halogens, -CHO, -COOH, -NO2, -CN

#18
正面 (问题)

why is there a difference between conditions for the same electrophilic substitution reactions for benzene and methylbenzene?

背面 (解答)

• since the -CH3 group is activating, the conditions for it to undergo electrophilic substitution are milder compared to those for benzene • activating groups like -CH3 increase the electron density of the benzene ring, making it more reactive towards electrophilic attack, hence milder conditions are needed

#19
正面 (问题)

how do substituents on a benzene ring affect the position of the incoming electrophile of monosubstitued arenes?

背面 (解答)

the position of the incoming group is determined by the nature of the substituent/group already bonded to the ring, NOT by the nature of the incoming group!!! activating groups are 2,4-directing groups while deactivating groups are 3-directing groups. if there are 2 groups already on the benzene ring, - if both groups direct to the same position, substitution will occur there - if each group directs the incoming electrophile to a different position, the major product follows the directing effect of the more strongly activating group - further subsitution rarely occurs between 2 groups in 1,3-disubstituted benzene rings as the site is too sterically hindered the data booklet contains a table that summarises the effects and position of substitution by he group alreaedy on the benzene ring (don’t have to memorise!)

#20
正面 (问题)

what are the reagents, conditions & observations for side chain free radical substitution of methylbenzene with chlorine?

背面 (解答)

reagents & conditions: - Cl2 (g), UV light/heat observation: - greenish-yellow Cl2 (g) decolourises slowly

#21
正面 (问题)

what are the reagents, conditions & observations for side chain free radical substitution of methylbenzene with bromine?

背面 (解答)

reagents & conditions: - Br2 (l), UV light/ heat observation: - reddish-brown Br2 (l) decolourises slowly

#22
正面 (问题)

what are the reagents, conditions & observations for side chain oxidation of methylbenzene?

背面 (解答)

oxidation to benzoic acid reagents & conditions: - KMnO4 (aq), dilute H2SO4, heat observations: - purple KMnO4 is decolourised - white precipitate of benzoic acid is formed oxidation to benzoate salt reagents & conditions: - KMnO4 (aq), dilute NaOH, heat observations: - purple KMnO4 is decolourised - brown precipitate of manganese dioxide, MnO2 (s) is formed

#23
正面 (问题)

how can bromine in tetrachloromethane be used to differentiate between alkenes and arenes?

背面 (解答)

procedure: add bromine in tetrachloromethan dropwise with shaking to 1cm3 of each compound in separate test tubes observations: for benzene, Br2 in CCl4 remains reddish-brown. for the alkene, reddish-brown Br2 in CCl4 decolourises.

#24
正面 (问题)

how can aqueous bromine be used to distinguish between alkenes and arenes?

背面 (解答)

procedure: add aqueous bromine dropwise with shaking to 1cm3 of each compound in separate test tubes. observations: for benzene, BR2 (aq) remains yellow-orange. for the alkene, yellow-orange Br2 (aq) decolourises note that for aqueous bromine, if qns ask for equation, must include H2O!! so reactants would be Br2 + H2O