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5.1.1 - How fast

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卡片总数: 24内容版本: v4公开卡包更新时间: 8/1/2026

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#1
正面 (问题)

Order of a reaction

背面 (解答)

The power to which a conc. of a reactant is raised to in the rate equation

#2
正面 (问题)

1st order graphs

背面 (解答)

Slightly downward slope (conc vs. time graph) Drops w/ a constant half life Rate=conc; diagonal line in rate vs. conc graph

#3
正面 (问题)

2nd order graphs

背面 (解答)

Decline steeply then level off Parabola in rate vs. conc graph

#4
正面 (问题)

2nd order

背面 (解答)

Rate is proportional to the square of the con. (upward slope)

#5
正面 (问题)

Zero order graphs

背面 (解答)

Constant decline in conc. (conc vs. time) Rate is independent of [] Rate stays constant in rate vs. conc graph

#6
正面 (问题)

Overall order

背面 (解答)

Obtained by adding all the orders of the reactants

#7
正面 (问题)

Rate eqn.

背面 (解答)

Rate = k [A]^m [B]^n Includes all reactants up to and including the rate determining step May include catalysts

#8
正面 (问题)

Rate constant

背面 (解答)

A number that allows the equation to work. It is unchanged by changes to concentration but will increase at higher temperatures

#9
正面 (问题)

Rate of reaction

背面 (解答)

Speed at which a reactant is destroyed Speed at which a product is formed conc/dm^3 s^1

#10
正面 (问题)

Half life of a reaction

背面 (解答)

Time it takes for the concentration of a reactant to halve

#11
正面 (问题)

Rate determining step

背面 (解答)

Reaction that occurs at a much slower rate and requires a much higher activation energy

#12
正面 (问题)

Finding k using [conc] vs time graph

背面 (解答)

k = ln (2)/ half life

#13
正面 (问题)

Units of k

背面 (解答)

s^-1 Increases w/ temp

#14
正面 (问题)

Finding k using rate vs conc graphs

背面 (解答)

Gradient = m = k

#15
正面 (问题)

Initial rates method

背面 (解答)

We always take the initial rate as that’s the maximum rate Allows us to make a comparison of the effect of any changes of conditions as the rate changes during the reaction

#16
正面 (问题)

Colorimetry

背面 (解答)

Measures absorbancy (and loss of colour) and you can see how this changes with conc

#17
正面 (问题)

Units for zero order reaction

背面 (解答)

mol dm-3 s-1

#18
正面 (问题)

Units for first-order reaction

背面 (解答)

s-1

#19
正面 (问题)

Units for second order reaction

背面 (解答)

mol -1 dm3 s-1

#20
正面 (问题)

Units for third order reaction

背面 (解答)

dm6 mol-2 s-1

#21
正面 (问题)

Why is it better to measure a physical property than to do a chemical analysis of the reaction

背面 (解答)

Chemical requires reaction to stop Physical does not interfere w/ progress

#22
正面 (问题)

Why do we use a little ‘clock reactant’ (PAG 10.1)

背面 (解答)

So that the colour change happens as close to the inital rate as possible as the colour change begins when all he S2O8 2- ions have been used up. It is only then the I2 can react w/ the starch

#23
正面 (问题)

Finding reaction mechanism

背面 (解答)

Mechanism adds up to overall If species is both on reactants and products side, cancel out Reactants in rate eqn are reactants of RDS

#24
正面 (问题)

Linking k and T

背面 (解答)

As T increases as does k and therefore so does the rate If Ea is reduced, k increases For every 10 degree rise in T, k is doubled as is the rate T and k have a +ve exponential relationship