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Classical Probability
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Total cards: 3•Content version: v4•Public deck•Updated: 8/1/2026
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#1
Front (Question)
Probability with equally likely outcomes
Back (Answer)
|S|= number of elements of S |A|= number of elements of A A is a subset of S P(A) = |A|/|S|
#2
Front (Question)
Permutations
Back (Answer)
Suppose now that we have n objects. There are n(n − 1)(n − 2) · · · 3 · 2 · 1 = n! different permutations of the n objects.
#3
Front (Question)
Combinations
Back (Answer)
Notation and terminology We define (n r), for r < n, by (n r) = n! / (n − r)! r! and say that (n r) –> (read as “n choose r”) represents the number of possible combinations of n objects taken r at a time.