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Spectroscopic Techniques

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Total cards: 21•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (21)

#1
Front (Question)

What are the two types of scattering?

Back (Answer)

• Rayleigh: elastic - leaves the molecule in the same state • Raman: inelastic - leaves the molecule in a different quantum state

#2
Front (Question)

What are photons produced from?

Back (Answer)

• electromagnetic radiation

#3
Front (Question)

What do photons do in electromagnetic radiation?

Back (Answer)

interact with molecular vibrations in a material and are scattered

#4
Front (Question)

What is Raman scattering photon?

Back (Answer)

has a different energy to that of the incident photon

#5
Front (Question)

What are the two types of Raman scattering?

Back (Answer)

• Stokes: the photon has lost energy to the molecule • Anti-Stokes: the photon has gained energy from the molecule

#6
Front (Question)

What happens when a photon interacts with a molecule in Raman scattering?

Back (Answer)

they go into a virtual state and then drop back down to the ground state

#7
Front (Question)

What happens in stokes scattering?

Back (Answer)

start at a lower vibrational state, then enter a virtual state, then fall back down to a higher vibrational state than at the start

#8
Front (Question)

What happens in anti-stokes scattering?

Back (Answer)

starts at a higher vibrational state, then enters a virtual state, then falls back down to a lower vibrational state than at the start

#9
Front (Question)

What is the type of scattering that majority of light scattered with?

Back (Answer)

Rayleigh

#10
Front (Question)

What are the different molecular vibrations?

Back (Answer)

• symmetric stretching • antisymmetric stretching • in-plane scissoring • in-plane rocking • out-of-plane wagging • out-of-plane twisting

#11
Front (Question)

What must a molecule be to be Raman active?

Back (Answer)

anisotropic polarisability - change in polarisation

#12
Front (Question)

What must a molecule be to be IR active?

Back (Answer)

change in dipole

#13
Front (Question)

What is the mutual exclusion rule?

Back (Answer)

in a centrosymmetric molecule a vibrational mode may be either Raman or IR active but it cannot be both

#14
Front (Question)

What happens when a mode is active in both Raman and IR?

Back (Answer)

one tends to be weak and the other tends to be strong - e.g. water

#15
Front (Question)

Raman vs IR

Back (Answer)

Raman * light scattering * requires a change in polarisability * little or no sample prep needed * measure through transparent packaging * aqueous samples IR * IR absorption * requires change in dipole moment * sample preparation needed * short optical path length required * non-aqueous samples

#16
Front (Question)

How does a Raman spectrometer work?

Back (Answer)

• laser source (blue, green, red) produces light which hits focusing mirror, goes through a beam splitter and hits more mirrors to hit the sample • light interacts with sample and scatters the light • Rayleigh filter filters out the Rayleigh svattered light • charged couple detector takes light and converts it inot an electrical change to produce a signal, algorithm turns it into a spectrum

#17
Front (Question)

Order the forms of scattering in terms of strength

Back (Answer)

• Rayleigh • Stokes • anti-stokes

#18
Front (Question)

What does Raman ususally look at?

Back (Answer)

inorganics but can also look at organics

#19
Front (Question)

How do you assign functional groups with Raman?

Back (Answer)

complementary to IR spectra

#20
Front (Question)

Why would you use Raman microspectroscopy?

Back (Answer)

• rapid • non-destructive • high spatial resolution • inorganic/organic profiling • sensitive • minimal sample preparations • suitable for databasing • chemometrics • parameter optimisation • automated stage mapping • material identification • sample matching and heterogeneity • structure determination • forgery detection

#21
Front (Question)

Why is chemometrics used for Raman and IR spectrums?

Back (Answer)

• group similar samples • gets rid of bias and difference of opinions • use it to identify an unknown • useful for small spectral differences that are difficult to distinguish visually