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atomic structure and electron configuration

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卡片总数: 17内容版本: v4公开卡包更新时间: 8/1/2026

卡片预览 (17 张)

#1
正面 (问题)

atomic number =

背面 (解答)

number of protons

#2
正面 (问题)

number of protons=

背面 (解答)

number of electrons(in neutral atom)

#3
正面 (问题)

Isotopes

背面 (解答)

atoms of the same element which contain different number of neutrons

#4
正面 (问题)

of neutrons =

背面 (解答)

mass number - atomic number

#5
正面 (问题)

in isotope notation state where the mass # is and the atomic number

背面 (解答)

mass number on the top atomic number below mass number

#6
正面 (问题)

how are ions formed

背面 (解答)

when atoms gain or lose electrons when reacting chemically

#7
正面 (问题)

in ionically charge atoms does # of protons equal # of electrons

背面 (解答)

no

#8
正面 (问题)

how to find relative atomic mass?

背面 (解答)

divided percentages by 100 then multiply that number by the mass number that goes along with that percentage. there should be addition between each parenthesis

#9
正面 (问题)

energy level shell: max # of electrons

背面 (解答)

1:2 2:8 3:18 4:32 energy level on left, max # of electrons on right

#10
正面 (问题)

sub level: max # of electrons

背面 (解答)

S:2 P:6 D:10 F:14

#11
正面 (问题)

which level gets removed before: level 4 electrons or 3d

背面 (解答)

level 4, because level is lower in energy due to less electron repulsion

#12
正面 (问题)

electron configuration example

背面 (解答)

1s2,2s2,3p6 and so on

#13
正面 (问题)

Chronium electron configuration(24e)

背面 (解答)

1s2,2s2,2p6,3s2,3p6,4s1,3d5 instead of having 4s2 ad 3d4 write 4s1 3d5 same goes with copper: write 4s1 3d9

#14
正面 (问题)

Orbitals

背面 (解答)

think of them as the boxes can only contain a max of two electrons in each box

#15
正面 (问题)

sub level: # of orbitals

背面 (解答)

S:1 P:3 D:5 F:7

#16
正面 (问题)

drawing of orbitals( explain what the 4 different variations are

背面 (解答)

S= spherical Px= dumbbell across x axis Py= dumbbell across y axis Pz= diagonal dumbell

#17
正面 (问题)

electron configuration of ions

背面 (解答)

if the charge is + then remove if the charge is negative then add