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Diastereocontrol in Cyclic systems 1

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (24)

#1
Front (Question)

What is a challenge with stereocontrol involving a carbonyl group e.g. ketone with a stereocentre +NaBH4

Back (Answer)

• To achieve a stereoselective reaction at the carbonyl group, the existing stereocentre would have to influence the direction of attack of the nucleophile at the C=O group • Hard as 3 bond separation and carbon chain is highly flexible- able to access many different conformations - produced racemic mixture

#2
Front (Question)

How can you increase the stereocontrol of a carbonyl molecule

Back (Answer)

• Join the ends of the molecule into a ring • A cyclic molecule is much less flexible and has only one low energy conformation in a lot of cases e.g. T-bu is a conformational-biasing group as has 99% preference for equatorial

#3
Front (Question)

How should you draw cyclohexanones

Back (Answer)

• C=O group at pointy end of chiar bisecting the angle between axial and equatorial • Flat carbon as sp2 hybridised

#4
Front (Question)

Which direction do small and large nucleophiles attack from

Back (Answer)

• Small nucleophiles = axially • Large nucleophiles = equatorially

#5
Front (Question)

Why do large nucleophiles attack equatorially

Back (Answer)

• Large nucleophile attack suffers steric interactions with diaxial hydrogens during axial attack

#6
Front (Question)

Why do small nucleophiles prefer axial attack on cyclohexanones

Back (Answer)

• C=O bond in cyclohexanone is not exactly co-planar with the neighbouring C-H bonds- 4 degrees below • During axial attack, the onset of rehybridization form sp2 to sp3 pushes the C=O group downwards away from the neighbouring C-H • But opposite is true for equatorial attack as torsional strain increase in he TS as the molecule begins to pass through an unfavourable eclipsed conformation

#7
Front (Question)

What does torsional steering mean

Back (Answer)

• Describes reactions whose selectivity is governed by minimisation of developing torsional strain interactions in the TS

#8
Front (Question)

What is torsional strain

Back (Answer)

• Strain caused by the close approach of atoms or groups separated by three covalent bonds. • In the molecule W-X-Y-Z, atoms W and Z may experience torsional strain if a particular conformation (such as an eclipsed conformation) brings these atoms into close proximity.

#9
Front (Question)

Do these carbon nucleophiles prefer axial or equatorial attack: Li-Alkyne Me-Li Phenyl-Li Me-MgBr t-Bu-MgBr

Back (Answer)

• Li-Alkyne = Axial - v small • Me-Li = 35% axial • Phenyl-Li = 42% axial - behaves smaller than you would think as flat • Me-MgBr = 41% axial • t-Bu-MgBr = 0% axial - v large

#10
Front (Question)

What are the small = axial attack etc arguments relevant for

Back (Answer)

• IRREVERSIBLE ADDITION • under kinetic control - to do with activation height of energy barrier

#11
Front (Question)

When does is attack on a cyclohexanone provide the thermodynamic (most stable) product

Back (Answer)

• reversible reaction • involving configurationally labile reactive intermediates (radicals)

#12
Front (Question)

Describe electrophilic additions to cyclohexenes

Back (Answer)

• Bromine and related electrophiles add to cyclohexenes in a trans-diaxial fashion • Goes through a favoured chair-like TS - Produces diaxial chair product • Diequatorial addition goes through twist-boat-like TS, then produces diaxial twist boat - which forms diequatorial chair- equilibrium

#13
Front (Question)

Which of diaxial and diequatorial products in electrophilic addition to cyclohexenes is favoured

Back (Answer)

• Both pathways are stereoelectronically-mandated to give trans-diaxial products • But through the chair-like transition state is faster as the TS is lower in energy

#14
Front (Question)

Describe alkylations of cyclohexanone enolates

Back (Answer)

• For cyclohexanone-derived enolates, axial attack of electrophile is stereoelectronically required • Only way that electrophiles can interact productively with the Pi-orbital • But selectivity for alkylation of cyclohexanones is much poorer than for bromination - 55% axial favoured compared to 96%

#15
Front (Question)

Why is the selectivity for alkylation of cyclohexanones much poorer than for bromination

Back (Answer)

• Poor selectivity in the enolate alkylation reflects the very early nature of the TS- Occurs much earlier on the reaction coordinate • Therefore the TS looks much more like the enolate than the products • The reaction does therefore not feel the developing strain with the twist-boat product so much • Therefore less differentiation between the competing TSs leading to lower selectivity

#16
Front (Question)

Why does enolate alkylations have early TS

Back (Answer)

• Mainly because the alkylation step is so exothermic • As we regenerate a very stable C=O bond from the less strong C=C bond in the enolate ion • We make a strong C-C bond at the expense of a much weaker C-I bond • In general exothermic = earlier transition states

#17
Front (Question)

What is an alternative strategy for alkylation of cyclohexanone enolates to improve selectivity

Back (Answer)

• Use enamines as nucleophiles • Much less reactive than lithium enolates- later TS

#18
Front (Question)

What is an alternative strategy for alkylation of cyclohexanone enolates to improve selectivity

Back (Answer)

• Use enamines as nucleophiles • Much less reactive than lithium enolates- later TS • Produces trans isomer

#19
Front (Question)

What is a problem with using enamines as nucleophiles in the alkylation of cyclohexanone

Back (Answer)

• Issue with competing N-alkylation when using simple alkyl halides which lowers the yield

#20
Front (Question)

What are the steps in the alkylation of cyclohexanone enolates using enamines

Back (Answer)

• Add pyrrolidine to produce an enamine • Add Alkylhalide to form iminium salt • Add H3O+ to produce the trans isomer • Then N-alkylated enamine is the major product though

#21
Front (Question)

How can the cis-isomer product of a cyclohexanone be accessed

Back (Answer)

• Rely on thermodynamic control via base-catalysed epimerisation • First LDA, THF then MEI • Produces not stereoselective trans isomer • Then add NaOMe, MeOH to produce cis isomer - reversible reaction

#22
Front (Question)

What is another cyclic compound whihc is attacked axialy

Back (Answer)

• Cyclic oxocarbenium ions • Formed in SN1 processes from cyclic acetals under acidic conditions • Attack on double bond to give a chair like TS

#23
Front (Question)

What would reverse process of axial attack on cyclic oxocarbenium ions look like

Back (Answer)

• Expulsion of a leaving group to give an oxocarbenium ion must also proceed from the axial isomer • Forward and reverse reactions share the same TS • Principle of microscopic reversibility

#24
Front (Question)

Describe conjugate additions to cyclohexenones

Back (Answer)

• The principle of axial attack can be extended to cyclohexenones which contain 3 contiguous sp2 centres- hence 5 co-planar ring atoms in a so-called envelope conformation