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3.1.4 Energetics

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

Define Enthalpy

Back (Answer)

Heat content in a substance

#2
Front (Question)

Define Enthalpy Change (ΔH)

Back (Answer)

Change in heat energy (of a reaction) at a constant pressure

#3
Front (Question)

State the units for enthalpy change (ΔH)

Back (Answer)

kJ mol-1

#4
Front (Question)

What is meant by this symbol ⦵?

Back (Answer)

Means substances were in their standard states and measurement was under standard conditions

#5
Front (Question)

Name the standard conditions

Back (Answer)

• 1 atm (100 kPa) • 298 K

#6
Front (Question)

Exothermic: ΔH is ______

Back (Answer)

negative

#7
Front (Question)

Endothermic: ΔH is ______

Back (Answer)

positive

#8
Front (Question)

Give 2 examples of exothermic reactions

Back (Answer)

• Neutralisation • Combustion

#9
Front (Question)

Give 2 examples of endothermic reactions

Back (Answer)

• Thermal decomposition • Photosynthesis

#10
Front (Question)

Sketch a graph to show an exothermic reaction

Back (Answer)

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#11
Front (Question)

Sketch a graph to show an endothermic reaction

Back (Answer)

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#12
Front (Question)

Why is bond breaking endothermic (ΔH = positive)?

Back (Answer)

Need energy to break bonds

#13
Front (Question)

Why is bond making exothermic (ΔH = negative)?

Back (Answer)

Energy released when bonds formed

#14
Front (Question)

If more energy is needed to break bonds than is released when bonds made, ΔH is _____

Back (Answer)

positive (If it’s less = ΔH is negative)

#15
Front (Question)

Define standard enthalpy of formation (ΔfH⦵)

Back (Answer)

Is the enthalpy change when 1 mole of a compound is formed from its constituent elements under standard states & standard condition

#16
Front (Question)

Define standard enthalpy of combustion (ΔcH⦵)

Back (Answer)

Is the enthalpy change when 1 mole of a substance is burnt completely in oxygen, under standards states & standard conditions

#17
Front (Question)

Standard enthalpy of formation equation K2Cr2O7(l)

Back (Answer)

2K(s) + 2Cr(s) + 7/2O2(g) → K2Cr2O7(l)

#18
Front (Question)

Standard enthalpy of combustion equation CH4(g)

Back (Answer)

CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)

#19
Front (Question)

How do we use calorimetry to find how much heat is given by reaction?

Back (Answer)

By measuring temperature change

#20
Front (Question)

Describe how you can find the enthalpy of combustion of a flammable liquid using calorimetry

Back (Answer)

• Burn flammable liquid inside apparatus (e.g. calorimeter) • Then can work out heat energy that’s been absorbed by water (heat given by fuel as it burns = be absorbed by water)

#21
Front (Question)

Why is it hard to get an accurate result when using calorimetry? Name 3 reasons

Back (Answer)

• Heat is always lost to the surroundings • Combustion may be incomplete (less energy given out) • Flammable liquids often volatile = lose some fuel to evaporation

#22
Front (Question)

Describe how you can use calorimetry to calculate the enthalpy change for a neutralisation reaction

Back (Answer)

• Add known volume of acid to insulated container (e.g. polystyrene cup) & measure temperature • Add known volume of alkali and record temp. of mixture at regular intervals over period of time • Stir solution to make sure it’s evenly heated • Find temp change of experiment • Use it to calculate enthalpy change of reaction

#23
Front (Question)

Calorimetry Describe how you can use a graph to find an accurate temperature change

Back (Answer)

• During experiment, record temp at regular intervals • Start a couple mins before reaction • Plot graph of results • Draw 2 lines of best fit • 1 through points before reaction started • 1 through points after it started • Extend both lies so they both pass time when reaction started • Distance between 2 lines at time reaction (before any heat lost) = accurate temp change (ΔT) for reaction

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#24
Front (Question)

State what equation (& the units) you can use to calculate the enthaply change in calorimetry

Back (Answer)

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