Back to marketplace

27.3 Condensation Polymerisation

No description yet. This curated deck is ready for daily study.

Total cards: 18•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (18)

#1
Front (Question)

What is condensation polymerisation?

Back (Answer)

formation of polymer by joining of monomers with loss of small molecule

#2
Front (Question)

What atom(s) do amines lose during condensation reactions?

Back (Answer)

Card back image
#3
Front (Question)

What atom(s) do carboxylic acids lose during condensation reactions?

Back (Answer)

Card back image
#4
Front (Question)

What atom(s) do alcohols lose during condensation reactions?

Back (Answer)

Card back image
#5
Front (Question)

What is the main difference between addition polymerisation & condensation polymerisation?

Back (Answer)

addition reaction: monomers join without loss of small molecule condensation polymerisation: monomers join with loss of small molecule

#6
Front (Question)

Draw & label an ester linkage:

Back (Answer)

Card back image
#7
Front (Question)

Describe the formation of a polyester using 1 type of monomer:

Back (Answer)

monomer contains alcohol & carboxylic acid functional groups Ester linkages form between hydroxyl + carboxyl OH from carboxyl + H from alcohol ⟶ H2O (monomer could also be alcohol + acyl chloride, releasing HCl as small molecule)

#8
Front (Question)

Describe the formation of a polyester using 2 types of monomers:

Back (Answer)

MonomerA = dicarboxylic acid, MonomerB = diol Ester linkages formed during condensation between alternating dicarboxylic acid & diol

#9
Front (Question)

Draw & label an amide linkage:

Back (Answer)

Card back image
#10
Front (Question)

Describe the formation of a polyamide using 1 type of monomer:

Back (Answer)

monomer contains amine & carboxylic acid functional groups Amide linkages form between amine + carboxyl H from amine + OH from carboxyl ⟶ H2O (monomer could also be amine + acyl chloride, releasing HCl as small molecule)

#11
Front (Question)

Describe the formation of a polyamide using 2 types of monomers:

Back (Answer)

MonomerA = dicarboxylic acid, MonomerB = diamine Amide linkages formed during condensation between alternating dicarboxylic acid & diol

#12
Front (Question)

How many small molecules are released from the condensation polymerisation of n lots of monomerA only?

Back (Answer)

n-1 (1 less than total monomers, because for 2 monomers there is 1 small molecule released)

#13
Front (Question)

How many small molecules are released from the condensation polymerisation between n(monomerA) + n(monomerB)?

Back (Answer)

2n-1 (1 less than number of total monomers, because for 2 monomers there is 1 small molecule released)

#14
Front (Question)

Draw the polymerisation reaction from 2-hydroxyethanoic acid monomers:

Back (Answer)

Card back image
#15
Front (Question)

Draw the polymerisation reaction from benzen-1,4-dicarboxylic acid + ethan-1,2-diol monomers:

Back (Answer)

Card back image
#16
Front (Question)

What 2 functional groups are used for synthesising polyesters?

Back (Answer)

carboxylic acid + alcohol (could also be acyl chloride + alcohol)

#17
Front (Question)

What 2 functional groups are used for synthesising polyamides?

Back (Answer)

carboxylic acid + amine (could also be acyl chloride + amine)

#18
Front (Question)

Draw the polymerisation reaction from 2-aminopropanoic acid monomers:

Back (Answer)

Card back image