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Coordination Chemistry

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Total cards: 18•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

what are isomers

Back (Answer)

Isomers are two or more compounds that have the same chemical formula but a different arrangement of atoms. Because of the different arrangement of atoms, they differ in one or more physical or chemical properties. Two principal types of isomerism are known among coordination compounds. (a) Stereoisomerism (i) Geometrical isomerism (ii) Optical isomerism (b) Structural isomerism (i) Linkage isomerism (ii) Coordination isomerism (iii) Ionisation isomerism (iv) Solvate isomerism

#2
Front (Question)

stereoisomers and structural isomers

Back (Answer)

Stereoisomers have the same chemical formula and chemical bonds but they have different spatial arrangement. Structural isomers have different bonds

#3
Front (Question)

Geometric Isomerism in square planar structures

Back (Answer)

This type of isomerism arises in heteroleptic complexes due to different possible geometric arrangements of the ligands. In a square planar complex of formula [MX2L2 ] (X and L are unidentate), the two ligands X may be arranged adjacent to each other in a cis isomer, or opposite to each other in a trans isomer as depicted in Fig. 5.2. Other square planar complex of the type MABXL (where A, B, X, L are unidentates) shows three isomers-two cis and one trans.

#4
Front (Question)

geometric isomerism in octahedral structures

Back (Answer)

octahedral complexes of formula [MX2L4 ] in which the two ligands X may be oriented cis or trans to each other This type of isomerism also arises when didentate ligands L – L [e.g., NH2 CH2 CH2 NH2 (en)] are present in complexes of formula [MX2 (L– L)2]

#5
Front (Question)

fac and mer isomer

Back (Answer)

Another type of geometrical isomerism occurs in octahedral coordination entities of the type [Ma3b3] like [Co(NH3)3(NO2)3]. If three donor atoms of the same ligands occupy adjacent positions at the corners of an octahedral face, we have the facial (fac) isomer. When the positions are around the meridian of the octahedron, we get the meridional (mer) isomer

#6
Front (Question)

Why is geometrical isomerism not possible in tetrahedral complexes having two different types of unidentate ligands coordinated with the central metal ion ?

Back (Answer)

Tetrahedral complexes do not show geometrical isomerism because the relative positions of the unidentate ligands attached to the central metal atom are the same with respect to each other.

#7
Front (Question)

optical isomers

Back (Answer)

Optical isomers are mirror images that cannot be superimposed on one another. These are called as enantiomers. The molecules or ions that cannot be superimposed are called chiral. The two forms are called dextro (d) and laevo (l) depending upon the direction they rotate the plane of polarised light in a polarimeter (d rotates to the right, l to the left). Optical isomerism is common in octahedral complexes involving 1,2,3 didentate ligands (Fig. 5.6). In a coordination entity of the type [PtCl2(en)2] 2+, only the cis-isomer shows optical activity

#8
Front (Question)

Linkage Isomerism

Back (Answer)

Linkage isomerism arises in a coordination compound containing ambidentate ligand. A simple example is provided by complexes containing the thiocyanate ligand, NCS– , which may bind through the nitrogen to give M–NCS or through sulphur to give M–SCN. Jørgensen discovered such behaviour in the complex [Co(NH3)5(NO2)]Cl2, which is obtained as the red form, in which the nitrite ligand is bound through oxygen (–ONO), and as the yellow form, in which the nitrite ligand is bound through nitrogen (–NO2).

#9
Front (Question)

Coordination Isomerism

Back (Answer)

This type of isomerism arises from the interchange of ligands between cationic and anionic entities of different metal ions present in a complex. An example is provided by [Co(NH3)6][Cr(CN)6], in which the NH3 ligands are bound to Co3+ and the CN– ligands to Cr3+. In its coordination isomer [Cr(NH3)6][Co(CN)6], the NH3 ligands are bound to Cr3+ and the CN– ligands to Co3+

#10
Front (Question)

Ionisation Isomerism

Back (Answer)

This form of isomerism arises when the counter ion in a complex salt is itself a potential ligand and can displace a ligand which can then become the counter ion. An example is provided by the ionisation isomers [Co(NH3)5(SO4)]Br and [Co(NH3)5Br]SO4 .

#11
Front (Question)

Solvate Isomerism

Back (Answer)

This form of isomerism is known as ‘hydrate isomerism’ in case where water is involved as a solvent. This is similar to ionisation isomerism. Solvate isomers differ by whether or not a solvent molecule is directly bonded to the metal ion or merely present as free solvent moleculesin the crystal lattice. An example is provided by the aqua complex [Cr(H2O)6 ]Cl3 (violet) and its solvate isomer [Cr(H2O)5Cl]Cl2 .H2O (grey-green).

#12
Front (Question)

disadvantages of werners theory

Back (Answer)

But his theory could not answer basic questions like: (i) Why only certain elements possess the remarkable property of forming coordination compounds? (ii) Why the bonds in coordination compounds have directional properties? (iii) Why coordination compounds have characteristic magnetic and optical properties? Many approaches have been put forth to explain the nature of bonding in coordination compounds viz. Valence Bond Theory (VBT), Crystal Field Theory (CFT), Ligand Field Theory (LFT) and Molecular Orbital Theory (MOT).

#13
Front (Question)

vbt

Back (Answer)

According to this theory, the metal atom or ion under the influence of ligands can use its (n-1)d, ns, np or ns, np, nd orbitals for hybridisation to yield a set of equivalent orbitals of definite geometry such as octahedral, tetrahedral, square planar and so on (Table 5.2). These hybridised orbitals are allowed to overlap with ligand orbitals that can donate electron pairs for bonding. It is important to note that the hybrid orbitals do not actually exist. In fact, hybridisation is a mathematical manipulation of wave equation for the atomic orbitals involved.

#14
Front (Question)

inner orbital/ low spin/ spin paired complex

Back (Answer)

In the formation of this complex, since the inner d orbital (3d) is used in hybridisation, the complex, [Co(NH3)6] 3+ is called an inner orbital or low spin or spin paired complex

#15
Front (Question)

outer orbital/ high spin/ spin free

Back (Answer)

The paramagnetic octahedral complex, [CoF6] 3– uses outer orbital (4d ) in hybridisation (sp 3 d 2 ). It is thus called outer orbital or high spin or spin free complex. Thus:

#16
Front (Question)

The spin only magnetic moment of [MnBr4] 2– is 5.9 BM. Predict the geometry of the complex ion ?

Back (Answer)

Since the coordination number of Mn2+ ion in the complex ion is 4, it will be either tetrahedral (sp 3 hybridisation) or square planar (dsp2 hybridisation). But the fact that the magnetic moment of the complex ion is 5.9 BM, it should be tetrahedral in shape rather than square planar because of the presence of five unpaired electrons in the d orbitals.

#17
Front (Question)

Limitations of Valence Bond Theory

Back (Answer)

(i) It involves a number of assumptions. (ii) It does not give quantitative interpretation of magnetic data. (iii) It does not explain the colour exhibited by coordination compounds. (iv) It does not give a quantitative interpretation of the thermodynamic or kinetic stabilities of coordination compounds. (v) It does not make exact predictions regarding the tetrahedral and square planar structures of 4-coordinate complexes. (vi) It does not distinguish between weak and strong ligands.

#18
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