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Textbook Ch.4: Reactions in Aqueous Solution

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

Molarity

Back (Answer)

the concentration of a solute in solution molarity (M) = moles of solute / liters of solution

#2
Front (Question)

What does the symbol [ ] represent?

Back (Answer)

the molarity of a species in solution

#3
Front (Question)

What can the molarity of a solution be used to calculate?

Back (Answer)

• The number of moles of solute in a given volume of solution • The volume of solution containing a given number of moles of solute

#4
Front (Question)

Precipitate

Back (Answer)

formed when two different ionic compounds are mixed, an insoluble solid separates out of a solution • The precipitate that forms is itself ionic • The cation comes from one solution, the anion comes from the other

#5
Front (Question)

Net ionic equation

Back (Answer)

the chemical equation that shows only those elements, compounds, and ions that are directly involved in the chemical reaction.

#6
Front (Question)

What does a net ionic equation have to show?

Back (Answer)

• Atom balance (same number of atoms of each element on both sides) • Charge balance (must be the same total charge on both sides)

#7
Front (Question)

Acid

Back (Answer)

a species that produces H⁺ ions in water solution

#8
Front (Question)

Base

Back (Answer)

a species that produces OH⁻ ions in a water solution

#9
Front (Question)

Strong acids

Back (Answer)

acids that ionize completely, forming H⁺ ions and anions

#10
Front (Question)

Weak acids

Back (Answer)

acids that only partially ionize to H⁺ ions in water

#11
Front (Question)

What does a double arrow ⇌ symbol mean?

Back (Answer)

the reaction does not go into completion, instead a mixture is formed containing significant amounts of both products and reactants

#12
Front (Question)

Strong bases

Back (Answer)

bases that completely ionize into OH⁻ ions and cations

#13
Front (Question)

Weak bases

Back (Answer)

produce OH⁻ ions by reacting with water molecules, acquiring H⁺ ions and leaving OH⁻ ions behind

#14
Front (Question)

Strong acid-strong base reactions

Back (Answer)

acids and bases both completely and the H⁺ and OH⁻ ions react with each other to form H₂O molecules, this reaction is referred to as neutralization

#15
Front (Question)

What is the net ionic equation for a strong acid-strong base reaction?

Back (Answer)

H⁺(aq) + OH⁻(aq) —> H₂O

#16
Front (Question)

Weak acid-strong base reactions

Back (Answer)

a two-step reaction occurs • Ionization of the weak acid into H+ and an anion • Neutralization of the H+ ions produced from (1) react with the OH- of the base to produce water

#17
Front (Question)

What is the net ionic equation for a weak acid-strong base reaction?

Back (Answer)

HB(aq) + OH⁻(aq) —> H₂O + B⁻(aq)

#18
Front (Question)

Strong acid-weak base reactions

Back (Answer)

two-step reaction occurs • Acid reacts with water to form cations and OH⁻ • Neutralization occurs when ions produced from (1) react with the OH⁻ of the base to produce water

#19
Front (Question)

What is the net ionic reaction for a strong-acid weak base reaction?

Back (Answer)

H⁺(aq) + B(aq) —> BH⁺(aq)

#20
Front (Question)

Titration

Back (Answer)

when acid-base reactions in water solution are commonly used to determine the concentration of a dissolved species or its percentage in a solid measure, so the volume of a standard solution (a solution of known concentration) required to react with a measured amount of sample is measured

#21
Front (Question)

Redox reaction

Back (Answer)

a reaction in an aqueous solution that involves a transfer of electrons between two species

#22
Front (Question)

Which species in a redox reaction is considered to be oxidized?

Back (Answer)

the species that loses (i.e. donates) electrons

#23
Front (Question)

Which species in a redox reaction is considered to be reduced?

Back (Answer)

the species that gains (i.e. received) electrons

#24
Front (Question)

How are redox reactions split?

Back (Answer)

it can be split into two half-equations, one of oxidation and the other of reduction