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Stoichiometry

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Total cards: 19•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (19)

#1
Front (Question)

What is relative atomic mass (Ar)?

Back (Answer)

average mass of naturally occurring atoms of an element on a scale where the 12C atom has a mass of exactly 12 units

#2
Front (Question)

What is relative molecular mass? (Mr)

Back (Answer)

sum of the relative atomic masses

#3
Front (Question)

What is relative formula mass?

Back (Answer)

Relative molecular mass for ionic compounds

#4
Front (Question)

How can solution concentrations be expressed?

Back (Answer)

mol/dm3 or g/dm3

#5
Front (Question)

Moles =

Back (Answer)

Concentration x Volume

#6
Front (Question)

What is a mole?

Back (Answer)

the number of particles which is equal to the number of atoms in 12g of carbon 12

#7
Front (Question)

What is Avogadro’s constant? (3)

Back (Answer)

number of particles / atoms / ions / molecules in one mole of a substance the number of particles / molecules in 24dm3 of a gas at RTP

#8
Front (Question)

What is the number of particles in 24 dm3 of a gas at RTP?

Back (Answer)

6 to 6.0^23 × 10^23 atoms (Avogadro’s constant)

#9
Front (Question)

no. of moles =

Back (Answer)

mass of substance taken/mass of one mole of substance

#10
Front (Question)

What is the limiting reactant?

Back (Answer)

the one that is not in excess

#11
Front (Question)

How can we calculate the limiting reactant?

Back (Answer)

Calculate which reactant has the lower number of moles

#12
Front (Question)

Excess of substance =

Back (Answer)

moles of substance at start - moles of substance at end

#13
Front (Question)

n =

Back (Answer)

M/mr

#14
Front (Question)

concentration =

Back (Answer)

number of moles / volume

#15
Front (Question)

volume of gas (in dm3) =

Back (Answer)

number of moles x 24

#16
Front (Question)

% by mass of element in compound =

Back (Answer)

sum of Mr/ relative formula mass of compound x 100

#17
Front (Question)

% yield =

Back (Answer)

actual yield/predicted yield x 100

#18
Front (Question)

% purity =

Back (Answer)

mass of pure product/mass of impure product x 100

#19
Front (Question)

What are the 6 formulas you need to know?

Back (Answer)

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