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M3 Enthalpy Changes Q&A

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Total cards: 6•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (6)

#1
Front (Question)

Explain, in terms of bond breaking and forming, why a particular reaction is exothermic.

Back (Answer)

• Breaking bonds requires/absorbs energy • Forming bonds releases energy • (In an exothermic reaction) more energy is released than required • OR: more energy is released by forming bonds than energy required by breaking bonds

#2
Front (Question)

Explain, in terms of bond breaking and forming, why a particular reaction is endothermic.

Back (Answer)

• Breaking bonds requires/absorbs energy • Forming bonds releases energy • (In an endothermic reaction) more energy is required than released • OR: more energy is required by breaking bonds than energy released by forming bonds

#3
Front (Question)

Why is the value of a standard enthalpy change of combustion, calculated from a calorimetry experiment, different to its data book value?

Back (Answer)

• Incomplete combustion • Heat loss • Non-standard conditions • Evaporation of water (or alcohol if liquid alcohol being combusted)

#4
Front (Question)

Suggest how the experiment design could be improved to improve the accuracy of the value of the standard enthalpy change of combustion?

Back (Answer)

• Burn in plentiful supply of oxygen • Improve insulation, e.g. draft shield, use copper can in place of beaker, use bomb calorimeter • Use standard conditions • Add lid to beaker • Use 3 DP balance (if masses in question given to 2 DP) or digital thermometer • Heat for longer to decrease % uncertainty in mass / temperature measurements

#5
Front (Question)

Why is the value of an enthalpy change, calculated using mean bond enthalpies, different to its data book value?

Back (Answer)

• Mean bond enthalpies are average values; they do not measure the exact value of the bond • Bonds have different strengths in different environments

#6
Front (Question)

Why is it not possible to measure the enthalpy change of formation directly, for the following reaction: N2(g) + ½O2(g) –> N2O(g)

Back (Answer)

• Activation energy is too high • Other products may be formed, e.g. NO, NO2